(1)
since both equations express y in terms of x, equate the right sides
- 2x = - 4x + 10 ( subtract 4x from both sides )
2x = 10 ( divide both sides by 2 )
x = 5
substitute x = 5 into y = - 2x → y = - 10
solution is : (x, y ) → (5, - 10 )
(2)
equate the right sides of both equations
3x = 2x - 7 ( subtract 2x from both sides )
x = - 7
substitute x = - 7 into y = 3x → y = - 21
solution is : (x, y) → (- 7, - 21)
(3)
substitute y = - 8 into the other equation
- 8 = 6x + 22 ( subtract 22 from both sides )
- 30 = 6x ( divide both sides by 6 )
x = - 5
solution is : (x, y ) → (- 5, - 8 )
Answer:
(3,5) (1,-2) (2,-3)
Step-by-step explanation:
hope this is right
Answer:
1. (AB) y = 2/3x + -4
Step-by-step explanation:
Formula - y = m(x) + (y-intercept)
m = rise / run
"run = horizontal (left and right)
rise = vertical (up and down)"
the y intercept is always going to be where y is 0 at. (x, y) you will use your x to determine the intercept
So lets use your first question as an example
1. (AB) y = m(x) + (y-int)
y = m(x) + (-4)
the point goes to the right 6 points and goes up 4 points (rise / run)
y = 4/6(x) + (-4)
You can round up the fraction to 2/3
y = 2/3(x) + -4
The answer is the letter C.
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A. Convert to vertex form:-
= -0.8(x^2 - 4x) + 6
= -0.8 ((x - 2)^2 - 4)) + 6
= -0.8(x - 2)^2 + 9.2
Maximum height of the ball is 9.2 feet Answer
b. horizontal distance at this height = 2 feet. Answer
c. this distance will be the positive root of f(x) = 0
-0.8(x - 2)^2 = -9.2
(x - 2)^2 = 11.5
xi-2 = sqrt 11.5 = 3.39
required distance = 5.39 = 5.5 feet answer
