Convert 1600 cm^3 to liters

Which is 2logx-6log(x-9) written as a single logarithm

Elena-2011 [213]

Answer: option c.

Step-by-step explanation:

To solve the given exercise and write the expression as a single logarithm, you must keep on mind the following properties:

$m*log(a)=log(a)^m$

$log(a)-log(b)=log(\frac{a}{b})$

Therefore, by applying the properties shown above, you can rewrite the expression given, as following:

$2logx-6log(x-9)=logx^2-log(x-9)^6=log(\frac{x^2}{(x-9)^6})$

Then as you can see, the answer is the option c.

3 0

3 years ago

Which of the following is an extraneous solution of StartRoot negative 3 x minus 2 EndRoot = x + 2? x = –6 x = –1 x = 1 x = 6

tester [92]

The extraneous solution is x=-1 and x=-6

Step-by-step explanation:

Given the question as;

$\sqrt{-3x-2} =x+2$

Eliminate the root in the left hand side

$(\sqrt{-3x-2}) =x+2\\\\\\(\sqrt{-3x-2} )^2=(x+2)^2\\\\-3x-2=x^2+4x+4\\\\0=x^2+4x+3x+4+2\\\\\\0=x^2+7x+6$

solve the quadratic equation by factorization

Find multiples of 6 that add up to 7-------- 1*6

Rewrite the equation as;

x²+7x+6=0

x²+6x+x+6=0

x(x+6) +1 (x+6) =0

(x+1)(x+6) =0

x+1=0

x=-1

or

x+6=0

x=-6

The roots are, x=-1, and x=-6

Learn More

Quadratic equations : brainly.com/question/1332667

Keywords : extraneous, solution

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5 0

3 years ago

Read 2 more answers

Do one of the following, as appropriate. (a) Find the critical value z Subscript alpha divided by 2, (b) find the critical v

babymother [125]

Answer:

We want to construct a confidence interval at 99% of confidence, so then the significance level would be $1-0.99 =0.01$ and the value of $\alpha/2 =0.005$ . And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

$z_{\alpha/2}= \pm 2.576$

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

Step-by-step explanation:

For this case we have the following info given:

$\alpha=0.01, n =26, \sigma = 28.9$

We want to construct a confidence interval at 99% of confidence, so then the significance level would be $1-0.99 =0.01$ and the value of $\alpha/2 =0.005$ . And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

$z_{\alpha/2}= \pm 2.576$

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

7 0

3 years ago

The stock market dropped 220 points on Monday. It lost another 48 points on Tuesday, and on Wednesday, it gained 96 points. What

Mariana [72]

Answer:

The amount of change was 172

8 0

3 years ago