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faust18 [17]
3 years ago
8

Which is 2logx-6log(x-9) written as a single logarithm

Mathematics
1 answer:
Elena-2011 [213]3 years ago
3 0

Answer: option c.

Step-by-step explanation:

 To solve the given exercise and write the expression as a single logarithm, you must keep on mind the following properties:

m*log(a)=log(a)^m

log(a)-log(b)=log(\frac{a}{b})

Therefore, by applying the properties shown above, you can rewrite the expression given, as following:

2logx-6log(x-9)=logx^2-log(x-9)^6=log(\frac{x^2}{(x-9)^6})

Then as you can see, the answer is the option c.

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2 years ago
If the first number is increased by 7 and the second number is reduced by 6 times, the sum of these numbers is 29.
Marta_Voda [28]

Answer:

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Second number = 12

Explanation:

Let the 1st number be x

Let the 2nd number be y

=====================

Condition 1

\sf \rightarrow  x + 7 + \dfrac{y}{6}  = 29

\rightarrow \sf x=-\dfrac{y}{6}+22

=====================

Condition 2

\rightarrow \sf 2y - (x - 5) = 9

\rightarrow \sf x = 2y -4

=====================

Substitute equations

\rightarrow \sf  -\dfrac{y}{6}+22 = 2y-4

\rightarrow \sf y=12

=====================

Find value of 1st number

\rightarrow \sf x = 2y - 4

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\rightarrow \sf x = 20

7 0
2 years ago
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Answer:

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Step-by-step explanation:

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and x represents the independent variable and y represents the dependent variable

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Agata [3.3K]
-64=(-4)³, w^12=(w^4)³
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