Answer its 82 i added the cm
<span>Answer:
y = x + sin(x)
y' = 1 + cos(x)
Setting y' to zero, we have:
y' = 0
1 + cos(x) = 0
cos(x) = -1
x = pi, on the interval [0, 2pi]
y'' = -sin(x)
When x = pi, y'' = -sin(pi) = 0
Thus, we have an extremum at x = pi, but it is neither a local maxima nor a local minima.
Notice as well that y' = 1 + cos(x) >= 1 for all real values of x.
Thus, y is an increasing function.
This implies that on the interval [0, 2pi], the absolute minima is at x = 0, where y = 0 + sin(0) = 0; and the absolute maxima is at x = 2pi, where y = 2pi + sin(2pi) = 2pi.</span>
Answer:
how to make a capacity of the ep of the ep of the ep of the ep of the ep of the ep of the ep
Answer:
Horizontal tangent
(x, y) = (1, 0)
Vertical tangent
(x, y) = DNE
Step-by-step explanation:
The equation for the slope (m) of the tangent line at any point of a parametric curve is:
Where 
and 
are the first derivatives of the horizontal and vertical components of the parametric curves. Now, the first derivatives are now obtained:
and 
The equation of the slope is:
As resulting expression is a linear function, there are no discontinuities and for that reason there are no vertical tangents. However, there is one horizontal tangent, which is:
The point associated with the horizontal tangent is:
The answer is:
Horizontal tangent
(x, y) = (1, 0)
Vertical tangent
(x, y) = DNE
