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3 years ago

What is 200 x 200? im so stupid...

Mathematics

2 answers:

MakcuM [25]3 years ago

6 0

The answer is 40000 and your not stupid if you need help that's okay

Svet_ta [14]3 years ago

3 0

200 x 200
= 40,000
you can jus multiply the 2 and put the all the zeros there

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Why is volume not a dose?

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concentration

Step-by-step explanation:

Because concentration is a factor to how much of a volume to give

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2 years ago

What are the first 50 digits of pi

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3 years ago

Read 2 more answers

The dimensions of rectangle A are four times the dimensions of rectangle B. The area of rectangle B is 162 cm2. What is the area

Anna [14]

Answer:

2,592 square cm.

Step-by-step explanation:

It is given that the dimensions of rectangle A are four times the dimensions of rectangle B.

Let dimensions of rectangle B are l×b.

So, the dimensions of rectangle A are 4l×4b.

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$Area=length\times width$

Area of rectangle B is

$A_B=l\times w$

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$A_B=l\times w=162$

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3 0

3 years ago

A garbage truck and a dump truck each drive along a straight road between two points. Using the points on a map that the city cr

Dmitriy789 [7]

We first find the lines of the motion of each truck, then calculate its intercept.
Garbage truck:
m = (12 - 4) / (5 - 3)
m = 4
4 - y = 4(3 - x)
4x - y = 8

Dump truck:
m = (33 + 3) / (-4 - 5)
m = -4
33 - y = -4(-4 - x)
4x + y = 17

Adding the two equations to solve them, we get:
8x = 25
x = 25 / 8

y = 17 - 4(25/8)
y = 17 - 25/2
y = 9/2

The trucks' point of intersection is (25/8,9/2)

7 0

3 years ago

An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 72 type K batteries and a sample of 49

rewona [7]

Answer:

Given:

For battery k(sample 1):

Sample size, n = 75

Sample mean, X' = 9.41

Standard deviation = 0.723

Mean u1 =???

For battery Q(sample 2):

Sample size, n = 49

Sample mean, X' = 9.69

Standard deviation = 0.257

Mean u2 =???

Significance level = 0.05

1) The null and alternative hypotheses, will be given as:

H0 : u1 - u2 = 0

H1 : u1 - u2 ≠ 0

2) This is a two tailed test.

For the test statistic, we have :

$Z_o = \frac{X'_1 - X'_2}{\sqrt{\frac{(\sigma_1)^2}{n_1} + \frac{(\sigma_2)^2}{n_2}}}$

$= \frac{9.41 - 9.69}{\sqrt{\frac{(0.723)^2}{75} + \frac{(0.257)^2}{49}}} = - 3.018$

≈ 3.02

The Zo = - 3.02

3) For the p value, using excel, we have:

2 * P(Z > (-3.018))

= 2 * NORMDIST (-3.018, 0, 1, true)

= 0.00254

For critical value:

Zcritical = Za/2 = 0.05/2

Zcritical = 0.025

We have alternative hypothesis,

H1 : u1 - u2 ≠ 0.

Therefore we reject null hypothesis H0 if Zo > Zcritical

4) We reject null hypothesis H0 if Zo > Zcritical. At 0.05 level of significance, there is not enough evidence to conclude that mean u1 and mean u2 are different.

4 0

3 years ago