Please help me, I do not know how to do this. I would appreciate it if you explained how you got your answer too…

Mathematics

1 answer:

Basile [38]2 years ago

8 0

Answer:

Step-by-step explanation:

DISCLAMER THIS IS ONLY FOR POINT THIS IS NOT THE RIGHT ASWEAR

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Zack deposited $1,200 in a savings account that paid 7.75% simple

Eddi Din [679]

<span>The correct answer is: Option (C) $1393.21

Explanation:
At the beginning of the Second year, the total balance would be:

$1200 + ($1200 * 7.75 / 100) = $1293

At the beginning of the Third year, the total balance would be:
$1293 + ($1293 * 7.75 / 100) = $1393.21 (Option C)</span>

6 0

4 years ago

Read 2 more answers

Triangle EFG has coordinates E (0, 0), F (0, 2), and G (3, 0). If ΔEFG ≅ ΔXYZ, what is the measure of XY?

andreev551 [17]

Answer:

2 units

Step-by-step explanation:

Since EFG and XYZ are congruent, we can write it like this:

E = X

F = Y

G = Z

Due to E and F being two units apart on the coordinate plane, we can conclude X and Y are also at a measurement of 2 units! Hope this helps!

4 0

3 years ago

An inequality is shown: −np − 4 ≤ 2(c − 3) Which of the following solves for n?

sesenic [268]

Answer:

$\huge\boxed{n\leq\dfrac{2-2c}{p}\ \text{for}\ p0}$

Step-by-step explanation:

$-np-4\leq2(c-3)\qquad\text{use the distributive property}\\\\-np-4\leq2c-6\qquad\text{add 4 to both sides}\\\\-np\leq2c-2\qquad\text{change the signs}\\\\np\geq2-2c\qquad\text{divide both sides by}\ p\neq0\\\\\text{If}\ p0 ,\ \text{then}\\\boxed{n\geq\dfrac{2-2c}{p}}$

6 0

3 years ago

Solve the equation 3^(2x) -4*3^(x+1) + 27 = 0. use rules of exponents to change 3^(x+1)

Leviafan [203]

Answer:

$\huge\boxed{x=1\ \vee\ x=2}$

Step-by-step explanation:

$3^{2x}-4\cdot3^{x+1}+27=0\\\\\text{use}\ (a^n)^m=a^{nm}\ \text{and}\ a^n\cdot a^m=a^{n+m}\\\\\left(3^x\right)^2-4\cdot3^x\cdot3^1+27=0\\\\\left(3^x\right)^2-12\cdot3^x+27=0\\\\\text{substitute}\ 3^x=t>0\\\\t^2-12t+27=0\\\\t^2-3t-9t+27=0\\\\t(t-3)-9(t-3)=0\\\\(t-3)(t-9)+0\iff t-3=0\ \vee\ t-9=0\\\\t-3=0\qquad\text{add 3 to both sides}\\\boxed{t=3}\\\\t-9=0\qquad\text{add 9 to both sides}\\\boxed{t=9}$