Question

Solve for x. −ax + 4b > 9 plz help me

Answer 1

Answer:

x < $\frac{9-4b}{a}$

Step-by-step explanation:

Given

- ax + 4b > 9 ( isolate the term in x by subtracting 4b from both sides )

- ax > 9 - 4b ( divide both sides by - a )

Remembering to reverse the inequality symbol when dividing by a negative quantity, thus

x < $\frac{9-4b}{a}$

Answer 2

$\bold{Answer}$

$\boxed{\bold{x$

$\bold{Explanation}$

• $\bold{Solve: \ -ax+4b>9}$

$\bold{---------------------}$

• $\bold{Subtract \ 4b \ From \ Both \ Sides}$

$\bold{-ax+4b-4b>9-4b}$

• $\bold{Simplify}$

$\bold{-ax>9-4b}$

• $\bold{Multiply \ Both \ Sides \ By \ -1 \ (Reverse \ Inequality)}$

$\bold{\left(-ax\right)\left(-1\right)$

• $\bold{Simplify}$

$\bold{ax$

• $\bold{Divide \ Both \ Sides \ By \ a;\quad \:a\ne \:0}$

$\bold{\frac{ax}{a}$

• $\bold{Simplify}$

$\bold{x$

$\boxed{\bold{Eclipsed}}$