3 years ago

Find the value.

Mathematics

1 answer:

grandymaker [24]3 years ago

7 0

For the second one I got 3.17

You might be interested in

Can someone help me!!

11Alexandr11 [23.1K]

75 ÷ 12.5 = 6
6 small jars = 1 large jar

3 0

3 years ago

Find the area of quadrilateral with vertices at points (3,0)(4,5)(-1,4)(-2,-1)

guapka [62]

Answer: 20

Step-by-step explanation:

Let 's complete our quadrilateral to a rectangle ; and subtract from it the area highlighted in red

$\displaystyle \rm S_{\diamond}=6\cdot 5 =30 \\\\ S_{ABCD}=30-(5:2+5:2+5:2+3:2+1\cdot1)=30-(7,5+1,5+1)=\\\\30-10=20 \\\\ S_{ABCD}=20$

4 0

3 years ago

Read 2 more answers

The square root of 30 times the square root of 3

NARA [144]

The answer is 9.48. also I rounded

6 0

4 years ago

Read 2 more answers

The triangle below are drawn on 1-cm dot paper. find the perimeter of each triangle

AnnyKZ [126]

There is no triangle below. Try to edit this problem.

4 0

3 years ago

Find the solutions for a triangle with a = 16, c =12, and B = 63º.

maks197457 [2]

Answer:

b. A = 71.6°; C = 45.40°; b =15.0

Step-by-step explanation:

The missing values can be found with the help of the Law of Cosine and properties of triangles:

Side b (Law of Cosine)

$b = \sqrt{a^{2}+c^{2}-2\cdot a \cdot c \cdot \cos B}$

$b = \sqrt{16^{2}+12^{2}-2\cdot (16)\cdot (12) \cdot \cos 63^{\circ}}$

$b \approx 15.022$

Angle A (Law of Cosine)

$\cos A = -\frac{a^{2} - b^{2}-c^{2}}{2\cdot b \cdot c}$

$\cos A = - \frac{16^{2}-15.022^{2}-12^{2}}{2\cdot (15.022)\cdot (12)}$

$\cos A = 0.315$

$A= \cos^{-1} 0.315$

$A \approx 71.639^{\circ}$

Angle C (Sum of internal angles in triangles)

$C = 180^{\circ} - 63^{\circ} - 71.639^{\circ}$

$C = 45.361^{\circ}$

Hence, the right answer is B.

6 0

4 years ago