Answer:
Part a) Higher fee per game Arcade A
Part b) Higher entrance fee Arcade B
Part c) Higher total cost for 8 games Arcade B
Step-by-step explanation:
Let
x------> the number of games
<em>Arcade A</em>
we have that the linear equation is
![y=0.75x+2](https://tex.z-dn.net/?f=y%3D0.75x%2B2)
The fee per game is $0.75
The entrance fee is $2
The cost for 8 games is equal to
![y=0.75(8)+2=\$8](https://tex.z-dn.net/?f=y%3D0.75%288%29%2B2%3D%5C%248)
Arcade B
Find the linear equation
Let
![A(0,8),B(4,10)](https://tex.z-dn.net/?f=A%280%2C8%29%2CB%284%2C10%29)
Find the slope of the line (fee per game)
![m=\frac{10-8}{4-0}=0.50](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B10-8%7D%7B4-0%7D%3D0.50)
The point A is the y-intercept
The linear equation is
![y=0.50x+8](https://tex.z-dn.net/?f=y%3D0.50x%2B8)
so
The fee per game is $0.50
The entrance fee is $8
The cost for 8 games is equal to
![y=0.50(8)+8=\$12](https://tex.z-dn.net/?f=y%3D0.50%288%29%2B8%3D%5C%2412)
therefore
Part a) Higher fee per game Arcade A
Part b) Higher entrance fee Arcade B
Part c) Higher total cost for 8 games Arcade B