Answer:
0.8340
Step-by-step explanation:
The aim of this question is to find the probability that the student makes it to the second class prior to when the lecture commences.
Provided that A, B, and C are independent of each other from the full complete question.
Then; we want P(A + C < B)
So A 
N (2, 1.5)
B N (10, 1)
C N (6, 1)
P(A + C - B < 0)
Since they are normally distributed( i.e. A + C - B)
Then;
E(A + C -B) = E(A) + E(C) - (B)
E(A + C -B) = 2 - 10 + 6
E(A + C -B) = -2
Var(A+C -B) = Var(A) + Var (B) + Var (C)
Var(A + C -B) = (1.5)² + (1)² + (1)²
Var(A + C -B) = 4.25
The standard deviation = 
The standard deviation = 2.06155
Answer: y = 2x + 5
Explanation:
The slope (number before x) is rise (change in y)/run (change in x). The rise is 6 and the run is 3, so the slope is 6/3, or 2.
The second blank is the y-intercept, or where the line crosses the vertical axis. This point is at 5.
Hope this helps!
3m+21=6m
=>21=6m-3m
=>21=3m
=>7=m
Therefore option A is the answer
Lets say that y represents length and x width.
From the text we can write:
y=x/6 - 1
Perimeter we calculate:
P = 2*x + 2*y
now we use y equation from above and put it in perimeter equation:
P = 2*x + 2*(x/6 - 1)
P = 2*(7x/6 - 1)
P = 7x/3 - 2
10^6 = 1,000,000
10^2 = 100
1,000,000 / 100 = 10,000
so 8.76x10^6 is 10,000 times greater than
