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lana [24]
2 years ago
8

What is the factorization of the expression below?

Mathematics
2 answers:
OverLord2011 [107]2 years ago
4 0

\large\red{\sf{4x^{2}-9y^{2}}}

\begin{gathered}\\ \sf\longmapsto 2^{2}x^{2}-3^{2}y^{2}\end{gathered}

\begin{gathered}\\ \sf\longmapsto (2x)^{2}-(3y)^{2}\end{gathered}

\begin{gathered}\\ \sf\longmapsto ⚘(2x-3y)×(2x+3y)\end{gathered}

Cloud [144]2 years ago
4 0

\sf \longmapsto \: 4x {}^{2}  - 9y  {}^{2}

  • There are no like terms so we can't simplify it
  • Factoring

\sf \longmapsto(2x+3y)(2x−3y)

\boxed{\sf (2x+3y)(2x−3y)}

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Step 1. First we need the mean. That's easy. Add them up and divide by the count. Check if you get 16.88/5 = 2.81333.

Step 2. Now we're going to subtract this from each of the values, and square the result. Don't worry about negative signs, the squaring will get rid of those. Example for the first number:

(1 - 2.813)^2 = 3.29

The list of numbers I get is (rounded, in reality round as little as possible):

3.29, 2.60, 1.41, 2.35, 1.66, 6.18

Step 3: Add them all up. I get 17.49. 
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TIP: Use excel to do all these steps, then run the set of numbers through Excel's built-in sd function (called  STDEV.P) and see that you get the same result!
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scZoUnD [109]

ANSWER:

EXPLANATION:

A simple random sample of size has mean and standard deviation. Construct a confidence interval for the population mean. The parameter is the population The correct method to find the confidence interval is the method.

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To construct a confidence interval for the population mean, first find out the margin of error of the sample mean. This is why you need a confidence interval. If you are 90% confident that the population mean lies somewhere around the sample mean then you construct a 90% confidence interval.

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If you are 95% sure that the population mean lies somewhere around the sample mean, your alpha level will be 0.05

In summary, get the values for sample size (n), sample mean, and sample standard deviation.

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Step-by-step explanation:

never heard of this equation

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