Answer:
800 bacteria
Step-by-step explanation:
Answer of this question depend upon number of hours at the end of day
Let Take Full Day of 24 hrs
Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)
Colby bacteria at end of day = 50 * 2¹²
Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)
Let say Jaquan bacteria at start of Day = J
Jaquan bacteria at end of day = J * 2⁸
Equating Both
J * 2⁸ = 50 * 2¹²
=> J = 50 * 2⁴
=> J = 50 * 16
=> J = 800
Jaquan will start with 800 Bacteria
Answer:
To find a, b, and c, rewrite in the standard form ax2+bx+c=0ax2+bx+c=0.
a=1, b=3, c=0
X - y = 7.....x = y + 7
x * y = 60
y(y + 7) = 60
y^2 + 7y = 60
y^2 + 7y - 60 = 0
(y + 12)(y - 5) = 0
y + 12 = 0
y = -12....not this one because it is negative
y - 5 = 0
y = 5 <===
x - y = 7
x - 5 = 7
x = 7 + 5
x = 12 <==
so ur 2 numbers are 12 and 5
Answer:
Each knight will 4.8 hrs spend on guard in one day
Step-by-step explanation:
A castle has to be guarded 24 hours a day 5 knights are ordered to split each day's guard duty equally
Each knights has to guard equally l.e for equal time .
That means 24 hours time has to be equally divided among the 5 knights
= 24 / 5 = 4.8
Each knight will spend on guard in one day = 4.8 hrs
Answer:
6x²y(9 - 2y)
Step-by-step explanation:
Step 1: Factor out GCF
6(9x²y - 2x²y²)
Step 2: Factor out <em>x²</em>
6x²(9y - 2y²)
Step 3: Factor out <em>y</em>
6x²y(9 - 2y)
And we have our factored answer.
