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pogonyaev
3 years ago
12

Brainliest if correct

Mathematics
1 answer:
PIT_PIT [208]3 years ago
6 0

\left(\dfrac{7}{4} \right)^{11} = \dfrac{7^{11}}{4^{11}}

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What is the perimeter of a triangle with the side lengths of 2, 5, and 10x?
olga55 [171]

The perimeter of a triangle with length of sides a, b and c:

P = a + b + c

a = 2, b = 5, c = 10x

Substitute:

P = 2 + 5 + 10x = 7 + 10x

<h3>Answer: 7 + 10x</h3>
4 0
3 years ago
Divide the 240g into the ratio 5:3:4?​
Leona [35]

5x+ 3x +4x =12x

12x =240

X=20

100:60:80

5 0
3 years ago
The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am
posledela

Step-by-step walkthrough:

a.

Well a standard half-life equation looks like this.

N = N_0 * (\frac{1}{2})^{t/p

N_0 is the starting amount of parent element.

N is the end amount of parent element

t is the time elapsed

p is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

N(t) = 74g * (\frac{1}{2})^{t/2.8days

b.

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2}  =  37g

c.

Now we just gotta do some algebra. Use the original function but this time, replace N(t) with 10g and solve algebraically.

10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}

Take the log of both sides.

log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})

Use the exponent rule for log laws that, log(b^x) = x*log(b)

log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})

\frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = \frac{t}{2.8days}

2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = t

slap that in your calculator and you get

t = 8.1 days

7 0
2 years ago
Is h(x)=x^-2-36, quadratic?
ValentinkaMS [17]
No it is not quadratic. because when you graph it it is not a parabola 
6 0
3 years ago
What the percentage of 3/5
fiasKO [112]
3 divide by 5 is 0.6 and you move the decimal two places to the right and your percentage is 60%
3 0
3 years ago
Read 2 more answers
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