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pogonyaev
3 years ago
12

Brainliest if correct

Mathematics
1 answer:
PIT_PIT [208]3 years ago
6 0

\left(\dfrac{7}{4} \right)^{11} = \dfrac{7^{11}}{4^{11}}

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I need help ? which linear function is represented by the graph?​
PilotLPTM [1.2K]
<h3>Answer: f(x) = (-1/2)x+1, choice B</h3>

=================================================

Explanation:

The diagonal line passes through 1 on the vertical y axis. So the y intercept is b = 1. This means the location of the y intercept is (0,1).

Start at (0,1) and move down 1 and to the right 2 to arrive at (2,0). This is another point on the diagonal line. The motion of "down 1 and right 2" is effectively the slope

slope = rise/run = -1/2

rise = -1, run = 2

The rise being negative means we have gone downhill as we move to the right.

With m = -1/2 as the slope and b = 1 as the y intercept, we go from y = mx+b to y = (-1/2)x+1

The last thing to do is replace y with f(x) to get f(x) = (-1/2)x+1 as the final answer.

4 0
3 years ago
Read 2 more answers
. A pedestal is built using a trapezoid-shaped base. Find the area of the trapezoid.
Igoryamba

18m^2

area of a trapezoid = (a+b)/2 * h, where a and b are bases 1 and 2, and h is height

(4+8)/2 * 3

= 12/2 * 3

= 6 * 3

= 18

4 0
2 years ago
Read 2 more answers
What is the length of the shadow cast by a 12-foot lamp post when the angle of elevation of the sun is 60º? (to the nearest tent
elena-s [515]

Answer:

6.9 foot.

Step-by-step explanation:

Given: Length of lamp post= 12-foot.

           The angle of elevation of the sun is 60°.

∴ The length of Lamp post, which is opposite is 12-foot.

  Now, finding the length of shadow cast by foot lamp.

Length of shadow is adjacent.

∴ We know the formula for Tan\theta= \frac{Opposite}{adjacent}

Next, putting the value in the formula.

⇒ Tan 60° = \frac{12}{adjacent}

Cross multiplying both side and using the value of Tan 60°

∴ Adjacent= \frac{12}{\sqrt{3} } = 6.92 ≅ 6.9 (nearest tenth value)

6.9 is the length of shadow cast by a 12-foot lamp post.

3 0
3 years ago
What is (12-2i) (5+3i) multiplied?
Ilya [14]
= 12*5 + 12*3i - 5*2i - 6i^2    (remember that i^2 = -1) so:-

= 60 +26i - 6*(-1)

= 60 + 26i + 6

= 66 + 26i
5 0
3 years ago
Andrew claims the initial value and y - intercept are the same thing on a graph. Is he correct?
Agata [3.3K]

Answer:

We conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

Step-by-step explanation:

We know that the initial value on a graph is basically the out-put value y of the point where the line meets or crosses the y-axis.

In other words, the initial value is the y-value or output of the point at x = 0

For example,

Let the equation

y = 2x+1

substitute x = 0

y = 2(0)+1

y = 0+1

y = 1

Thus, the initial value of the equation y = 2x+1 is: y = 1

Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

Thus, at y = 1, the line meets the y-axis.

Hence, the initial value of the line is: y = 1

Similarly, we know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

For example,

Let the equation

y = 2x+1

substitute x = 0

y = 2(0)+1

y = 0+1

y = 1

Thus, the y-intercept of y = 2x+1 is y = 1.

Please check the attached graph of the equation y = 2x+1.

It is clear from the graph that at x = 0, the value of y = 1.

Therefore, the y-intercept of y = 2x+1 is y = 1.

Conclusion:

Therefore, we conclude that the initial value and y-intercept are the same thing on a graph.

Please check the attached graph of the equation y = 2x+1.

6 0
3 years ago
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