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Svetllana [295]
2 years ago
14

Y+7=2(x+5) in standard form ​

Mathematics
1 answer:
Cerrena [4.2K]2 years ago
7 0

Answer:

2x-y=-3

Step-by-step explanation:

\mathrm{The\: standard\: form\: of\: a \:linear \:equation \:is}:\mathrm{A}x+\mathrm{B}y=\mathrm{C.}

\underline{\sf{Solve\:for\:}y}:

y+7=2(x+5)

=y+7=2x+2\cdot5

= y+7=2x+10

=(y+7)+(-7)=(2x+10)+(-7)

=y+7-7=2x+10-7

\underline{y=2x+3}

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Simplify 14 to the power of 15 over 14 to the power of 5
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Answer:

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{14}^{15-5}

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Step-by-step explanation:

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On each round, Ann and Bob each simultaneously toss a fair coin. Let Xn be the number of heads tossed in the 2n flips which occu
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Answer:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

Step-by-step explanation:

In a coin toss the  probability of tossing a head is 0.5 (50% head/50% tails)

If n is the number of rounds and 2n the number of coins tossed (one for each player), the probability of having m heads tossed is:

R=\frac{2n!}{m!*(2n-m)!}

R is the number of cases (combination of coins tossed) that gives a m number of heads. Each case has a probability of P_{case}=0.5^{2n} so:

P=\frac{2n!}{m!*(2n-m)!}*0.5^{2n}

<u>For example, to toss 4 heads in 5 rounds: </u>

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P=\frac{10!}{4!*(10-4)!}*0.5^{10}

P=\frac{10*9*8*7*6!}{4!*6!}*0.5^{10}

P=\frac{10*9*8*7}{4!}*0.5^{10}

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Answer:

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I'm not sure if that is exactly how you solve it but

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8 0
3 years ago
Read 2 more answers
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