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Sladkaya [172]
2 years ago
6

How much does the universe(galaxy) weigh?

Chemistry
2 answers:
AfilCa [17]2 years ago
7 0

Answer:

(before researching)it weighs a positive infinity ∞

Explanation:

(after researching)Our galaxy weighs in at around 10^42 kilograms and the entire visible universe reaches something like 10^53. You can try to convert those figures to something a little more familiar, such as the weight of a blue whale, by subtracting 5 from any of those exponents.

hope this helps have a great day also brainly would be very much appreciated

and here's a meme

nalin [4]2 years ago
4 0

Answer:  Universe

Mass of ordinary matter

The mass of the observable universe is often quoted as 1050 tonnes or 1053 kg. In this context, mass refers to ordinary matter and includes the interstellar medium (ISM) and the intergalactic medium (IGM). However, it excludes dark matter and dark energy.

Density (of total energy): 9.9×10−27 kg/m3 ...

Mass (ordinary matter): 1.5×1053 kg

Contents: Ordinary (baryonic) matter (4.9%); D...

Volume: 3.566×1080 m3

Explanation:  Galaxy

around 1.5 trillion solar masses

Their answer: The galaxy weighs around 1.5 trillion solar masses. This number helps put in perspective how very small we are. Take, for instance, where stars in the Milky Way fit in.

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Calculate the second volumes. <br> 7.03 Liters at 31 C and 111 Torr to STP
DIA [1.3K]

The second volume :    V₂= 0.922 L

<h3> Further explanation </h3><h3>Given </h3>

7.03 Liters at 31 C and 111 Torr

Required

The second volume

Solution

T₁ = 31 + 273 = 304 K

P₁ = 111 torr = 0,146 atm

V₁ = 7.03 L

At STP :  

P₂ = 1 atm

T₂ = 273 K

Use combine gas law :

P₁V₁/T₁ = P₂V₂/T₂

Input the value :

0.146 x 7.03 / 304 = 1 x V₂/273

V₂= 0.922 L

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3 years ago
For each pair, predict which molecule has the greater molar entropy under the same conditions (assume gaseous species).c o 2, ca
larisa [96]
I used to know this. I don't really remember but is used to know it. Im in 6th grade now
8 0
3 years ago
Which pair of aqueous solutions can create a buffer solution if present in the appropriate concentrations?.
Julli [10]

HF and NaF - If the right concentrations of aqueous solutions are present, they can produce a buffer solution.

<h3>What are buffer solutions and how do they differ?</h3>
  • The two main categories of buffers are acidic buffer solutions and alkaline buffer solutions.
  • Acidic buffers are solutions that contain a weak acid and one of its salts and have a pH below 7.
  • For instance, a buffer solution with a pH of roughly 4.75 is made of acetic acid and sodium acetate.
<h3>Describe buffer solution via an example.</h3>
  • When a weak acid or a weak base is applied in modest amounts, buffer solutions withstand the pH shift.
  • A buffer made of a weak acid and its salt is an example.
  • It is a solution of acetic acid and sodium acetate CH3COOH + CH3COONa.

learn more about buffer solutions here

<u>brainly.com/question/8676275</u>

#SPJ4

8 0
1 year ago
Calcular la presión final de un gas que inicialmente está a 21°C y 0,98 atm. Sabiendo que su temperatura aumenta a 37°C.
KatRina [158]

Answer:

1.03 atm

Explanation:

Primero <u>convertimos 21 °C y 37 °C a K</u>:

  • 21 °C + 273.16 = 294.16 K
  • 37 °C + 273.16 = 310.16 K

Una vez tenemos las temperaturas absolutas, podemos resolver este problema usando la<em> ley de Gay-Lussac</em>:

  • T₁P₂ = T₂P₁

En este caso:

  • T₁ = 294.16 K
  • P₂ = ?
  • T₂ = 310.16 K
  • P₁ = 0.98 atm

Colocando los datos:

  • 294.16 K * P₂ = 310.16 K * 0.98 atm

Y <u>despejando P₂</u>:

  • P₂ = 1.03 atm
7 0
2 years ago
Explain in terms of chemical reactivity why the elements in group 18 on the modern periodic table were not identified by Mendele
Makovka662 [10]

Answer:

elements tend not to react with other elements, there were no oxide compounds for Mendeleev to study. –Group 18 elements are generally unreactive. sodium ion is smaller because the sodium atom lost one electron. –An Na+ ion is smaller because it has one fewer electron shell.

Explanation:

can you me as brainliest if its right? i just need a few more to rank up! ^-^

Also have a great day and good luck in your studies!

6 0
2 years ago
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