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Sladkaya [172]
3 years ago
6

How much does the universe(galaxy) weigh?

Chemistry
2 answers:
AfilCa [17]3 years ago
7 0

Answer:

(before researching)it weighs a positive infinity ∞

Explanation:

(after researching)Our galaxy weighs in at around 10^42 kilograms and the entire visible universe reaches something like 10^53. You can try to convert those figures to something a little more familiar, such as the weight of a blue whale, by subtracting 5 from any of those exponents.

hope this helps have a great day also brainly would be very much appreciated

and here's a meme

nalin [4]3 years ago
4 0

Answer:  Universe

Mass of ordinary matter

The mass of the observable universe is often quoted as 1050 tonnes or 1053 kg. In this context, mass refers to ordinary matter and includes the interstellar medium (ISM) and the intergalactic medium (IGM). However, it excludes dark matter and dark energy.

Density (of total energy): 9.9×10−27 kg/m3 ...

Mass (ordinary matter): 1.5×1053 kg

Contents: Ordinary (baryonic) matter (4.9%); D...

Volume: 3.566×1080 m3

Explanation:  Galaxy

around 1.5 trillion solar masses

Their answer: The galaxy weighs around 1.5 trillion solar masses. This number helps put in perspective how very small we are. Take, for instance, where stars in the Milky Way fit in.

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2 years ago
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If you start with 163 g of water at 29◦C, how much heat must you add to convert all the liquid into vapor at 100◦C? Assume no he
Snowcat [4.5K]

Answer:

48.37514 kj

Explanation:

Given data:

Mass of water = 163 g

Initial temperature = 29°C

Final temperature = 100°C

Heat added = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Specific heat capacity of water is 4.18 j/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

ΔT =  100°C - 29°C

ΔT =  71°C

Q = 163 g × 4.18 j/g.°C × 71°C

Q = 48375.14 j

Joule to Kj conversion:

48375.14 /1000 = 48.37514 kj

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3 years ago
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Trial 3: 167.2 g

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8 0
3 years ago
How many moles of oxygen gas occupy 67.2 L of volume at STP?<br> A 0.333<br> B 3.00<br> C 1.00
posledela

Answer:

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Explanation:

have a good day btw i had this question before:D

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astraxan [27]

Answer:

2L of nitrogen gas will be needed

Explanation:

Based on the following reaction:

N₂ + 3H₂ → 2NH₃

<em>1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia.</em>

<em />

If 6L of hydrogen (In a gas, the volume is directly proportional to the moles, Avogadro's law) react, the volume of nitrogen gas required will be:

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