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3 years ago

How much does the universe(galaxy) weigh?

Chemistry

2 answers:

AfilCa [17]3 years ago

7 0

Answer:

(before researching)it weighs a positive infinity ∞

Explanation:

(after researching)Our galaxy weighs in at around 10^42 kilograms and the entire visible universe reaches something like 10^53. You can try to convert those figures to something a little more familiar, such as the weight of a blue whale, by subtracting 5 from any of those exponents.

hope this helps have a great day also brainly would be very much appreciated

and here's a meme

nalin [4]3 years ago

4 0

Answer: Universe

Mass of ordinary matter

The mass of the observable universe is often quoted as 1050 tonnes or 1053 kg. In this context, mass refers to ordinary matter and includes the interstellar medium (ISM) and the intergalactic medium (IGM). However, it excludes dark matter and dark energy.

Density (of total energy): 9.9×10−27 kg/m3 ...

Mass (ordinary matter): 1.5×1053 kg

Contents: Ordinary (baryonic) matter (4.9%); D...

Volume: 3.566×1080 m3

Explanation: Galaxy

around 1.5 trillion solar masses

Their answer: The galaxy weighs around 1.5 trillion solar masses. This number helps put in perspective how very small we are. Take, for instance, where stars in the Milky Way fit in.

You might be interested in

Which group in the periodic table contains the three elements with the highest electrical conductivities?

9966 [12]

Answer:

C Group 11

Explanation:

Group 11, by modern IUPAC numbering, is a group of chemical elements in the periodic table, consisting of copper (Cu), silver (Ag), and gold (Au).

These elements show highest electrical conductivity.

7 0

3 years ago

Vinegar contains 5g of acetic in 100mL of solution so the (w/v)% concentration is:

Andreyy89

The (w/v)% concentration of vinegar contains 5g of acetic in 100mL of solution is approx 0.5 %

<h3>What is Concentration ?</h3>

The concentration of a chemical substance expresses the amount of a substance present in a mixture.

There are many different ways to express concentration.(w/v)% is one of them.

Given ;

Mass of solute(acetic acid) is 5.0 g
Volume of solution is 100.0 mL.

We need to convert the grams of acetic acid to moles ;

Formula of acetic acid is CH₃COOH

Thus,

Molar mass of acetic acid = 2(12.01) + 4(1.01) + 2(16)

= 24.02 + 4.04 + 32

= 60.06 grams per mol

Moles of acetic acid = 5.0/60.06

= 0.083 moles

(w/v)% = 0.083 x 60 / 1000 x 100

= 0.498 %

= 0.5 %

Hence, The (w/v)% concentration of vinegar contains 5g of acetic in 100mL of solution is approx 0.5 %

Learn more about weight percentage here ;

brainly.com/question/22575652

#SPJ1

8 0

2 years ago

How many molecules of Iron(II)oxide are present in 35.2*10^-23 g of Iron (II)oxide?

slava [35]

Answer:

R.F.M of Iron (II) oxide :

${ \tt{ = (56 \times 2) + (16 \times 3)}} \\ = 160 \: g$

Moles :

${ \tt{ \frac{35.2 \times {10}^{ - 23} }{160} }} \\ = 2.2 \times {10}^{ - 24} \: moles$

Molecules :

${ \tt{ = 2.2 \times {10}^{ - 24} \times 6.02 \times {10}^{23} }} \\ = 1.3244 \: molecules$

4 0

3 years ago

A compound found in the athletes urine had a percent composition of 80.8% carbon, 8.97% hydrogen and 10.3% oxygen. What is the E

mojhsa [17]

Answer:

C21H2802

Explanation:

C=12g/mol

H=1g/mol

O=16g/mol

Part (C) of compound-80.18%

(0.8018 x 312)/12=21

Part (H) of compound-8.97%

(0.897 x 312)/1=28

Part (O) of compund-10.3%

(0.103 x 312)/16 = 2

Therefore the emp. formula is C12H28O2

8 0

3 years ago

Pa help thank yoeee <3333

Verizon [17]

Answer:

1.c

2.c

3.a

4.b

5.a

i think that's the answer

4 0

3 years ago