Its A Natural resources are found in abundance in the US.
The answer to your question:
1.88 moles Na is 43.22 grams
The average density of the peat moss in units of g/cm³ is 2.52 g/cm³
<h3>How to convert 40 lb to grams (g)</h3>
We'lol begin by converting 40 lb to grams (g). This can be obtained as follow:
1 lb = 453.592 g
Therefore,
40 lb = (40 × 453.592) / 1 lb
40 lb = 18143.68 g
<h3>How to convert 1.9 gal to cm³</h3>
We can convert 1.9 gal to cm³ as follow:
1 gal = 3785.41 cm³
Therefore,
1.9 gal = (1.9 gal × 3785.41 cm³) / 1 gal
1.9 gal = 7192.279 cm³
<h3>How to determine the density </h3>
The density can be obtained as follow:
- Mass = 18143.68 g
- Volume = 7192.279 cm³
- Density =?
Density = mass / volume
Density = 18143.68 / 7192.279
Density = 2.52 g/cm³
Learn more about density:
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<span>they both had their conclusions based on solid evidence</span>
Answer:
![K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BHCO_3%5E-%5D%7D%7B%5BH_2CO_3%5D%7D)
Explanation:
Several rules should be followed to write any equilibrium expression properly. In the context of this problem, we're dealing with an aqueous equilibrium:
- an equilibrium constant is, first of all, a fraction;
- in the numerator of the fraction, we have a product of the concentrations of our products (right-hand side of the equation);
- in the denominator of the fraction, we have a product of the concentrations of our reactants (left-hand side o the equation);
- each concentration should be raised to the power of the coefficient in the balanced chemical equation;
- only aqueous species and gases are included in the equilibrium constant, solids and liquids are omitted.
Following the guidelines, we will omit liquid water and we will include all the other species in the constant. Each coefficient in the balanced equation is '1', so no powers required. Multiply the concentrations of the two products and divide by the concentration of carbonic acid:
![K_a=\frac{[H_3O^+][HCO_3^-]}{[H_2CO_3]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BHCO_3%5E-%5D%7D%7B%5BH_2CO_3%5D%7D)