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2 years ago

Robert has 4 grams of a substance and Jill has 10 grams of the same substance. Which of the following statements is true?

2 answers:

5 0

If Robert has 4 grams of a substance and Jill has 10 grams of the same substance <span>Jill's sample will weigh more than Robert's sample.</span>

VLD [36.1K]2 years ago

5 0

Answer:

The correct answer is option is c.

Explanation:

Mass is defined as quantity of the matter contained by the body irrespective of its volume or any other forces acting on it.

Mass of substance Robert has = $m_1$ = 4 grams

Mass of same substance Jill has = $m_2$ 10 grams

4 grams < 10 grams

$m_1$

Sample of Jill is more in weight that the weight of the substance of Robert.

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How much water should be added to 4.3 moles of LiBr to prepare a 2.05 m solution?

arsen [322]

Answer:

2.1 kg of water

Explanation:

Step 1: Given data

Moles of lithium bromide (solute): 4.3 moles

Molality of the solution (m): 2.05 m (2.05 mol/kg)

Mass of water (solvent): ?

Step 2: Calculate the mass of water required

Molality is equal to the moles of solute divided by the kilograms of solvent.

m = moles of solute/kilograms of solvent

kilograms of solvent = moles of solute/m

kilograms of solvent = 4.3 mol /(2.05 mol/kg) = 2.1 kg

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2 years ago

In an ion with an unknown charge, the total mass of all the electrons was determined to be 2.19 ✕ 10−26 g, while the total mass

Ilya [14]

Answer:

$\large \boxed{\text{Fe$^{{2+}}$}}$

Explanation:

1. Number of electrons

$\text{Number of electrons} = 2.19 \times 10^{-26}\text{ g} \times \dfrac{\text{1 electron}}{9.109 \times 10^{-28}\text{ g}} = \text{24 electrons}$

2. Number of protons

$\text{Number of protons} = 4.34 \times 10^{-23}\text{ g} \times \dfrac{\text{1 proton}}{1.673 \times 10^{-24}\text{ g}} = \text{26 protons}$

3. Identify the ion

An atom with 26 protons is iron, Fe.

A neutral atom of iron would have 26 electrons.

The ion has only 24 electrons, so it has lost two. The ion must have a charge of +2.

$\text{The symbol for the ion is $\large \boxed{\textbf{Fe$^{\mathbf{2+}}$}}$}$

4 0

2 years ago

Consider the following reaction at 298K.

lakkis [162]

The true statements are;

K < 0
Eocel < 0

<h3>What is a redox reaction?</h3>

We define a redox reaction as one in which a specie is oxidized and another is reduced.

Now;

Eo cell = cell potential = -0.13 V - (+0.34 V) = -0.47 V

n =number of moles of electrons = 2 mole of electrons

K = equilibrium constant

ΔG = change in free energy

Eo cell = 0.0592/n log K

-0.47 = 0.0592/2 log K

log K = -0.47 * 2/0.0592

K = 1.3 * 10^-16

ΔG = -nFEo cell

ΔG = -(2 * 96500 * -0.47)

ΔG = 90.7kJ

Learn more about Ecell:brainly.com/question/10203847

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1 year ago

I need help ASAP 10 points

jekas [21]

Answer:

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2 years ago

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Elanso [62]

I belive this is called condensation.
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