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Nitella [24]
3 years ago
13

Solve the following differential equations using Laplace transforms. Assume zero initial conditions and that the forcing functio

ns are zero prior to t=0-.a. x(t) +7x (t) =5cos2tb. x(t) + 8 x(t) + 25x (t) =10u (t )
Mathematics
1 answer:
Rom4ik [11]3 years ago
7 0

Answer:

(A) X(S)=\frac{1.25}{S^2+4}

(B) X(S)=\frac{0.2941}{S}

Step-by-step explanation:

We have to find the Laplace transform

(a) x(t) + 7 x(t) = 5 cos2t

Taking Laplace of both side

X(X)+7X(S)=5\times \frac{2}{S^2+4}

8X(S)=\frac{10}{S^2+4}

X(S)=\frac{1.25}{S^2+4}

(B) x(t)+8x(t)+25x(t)=10u(t)

Taking Laplace transform of both side

X(S)+8X(S)+25X(S)=10\times \frac{1}{S}

34X(S)=\frac{10}{S}

X(S)=\frac{0.2941}{S}

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Answer:

3 feet.

Step-by-step explanation:

  • Base of the  triangular pennant = 1.5 feet long.
  • Area of the triangular pennant = 2.25 Square feet.

Now, we know that:

Area of a Triangle=\frac{1}{2}$ X Base X Height

Substituting the given values, we have:

2.25=\dfrac{1}{2}$ X 1.5 X Height\\\\2.25=$\dfrac{1.5}{2}$  X Height\\\\Cross multiply\\\\2.25*2=1.5  X Height\\\\Divide both sides by 1.5 to solve for the height\\\\\dfrac{2.25*2}{1.5}=\dfrac{1.5  X Height}{1.5}\\\\$Height of the Triangle =3 feet

Therefore, the height of the pennant is 3 feet.

5 0
3 years ago
Lenox ironed 1/4 of the shirts over the weekend. she plans to split the remainder of the work equally over the next 5 evenings.
Arisa [49]
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3 0
4 years ago
I need help with this question 1/2 + 2 3/4=?
enyata [817]

Answer:

3.25

Step-by-step explanation:

6 0
3 years ago
Their win percentage was 40, then how many matches did they play in all!
Neko [114]

Answer:

14400

Step-by-step explanation:

X - X × 75%=3600

X - X × \frac{75}{100} = 3600

X - \frac{3X}{4} = 3600

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3 0
3 years ago
Simplify (3v5+8v3−10v2)−(−12v5+4v3+14v2) . Write answer in standard form.<br> ​<br> ​
Tatiana [17]

Answer:

15v^5+4v^3-24v^2

Step-by-step explanation:

Distribute the Negative Sign:

=3v5+8v3−10v2+−1(−12v5+4v3+14v2)

=3v5+8v3+−10v2+−1(−12v5)+−1(4v3)+−1(14v2)

=3v5+8v3+−10v2+12v5+−4v3+−14v2

Combine Like Terms:

=3v5+8v3+−10v2+12v5+−4v3+−14v2

=(3v5+12v5)+(8v3+−4v3)+(−10v2+−14v2)

=15v5+4v3+−24v2

Answer:

=15v5+4v3−24v2

Hope this helps! :)

5 0
3 years ago
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