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slava [35]
2 years ago
10

The proof shows that opposite angles of a parallelogram are congruent. Given: ABCD is a parallelogram with diagonal AC. Prove: ∠

BAD ≅ ∠ DCB What is the missing reason In this partial proof? Question 3 options:
ASA Substution Angle Angle Postulate Alternate Interior Angles are Congruent
Mathematics
1 answer:
Rom4ik [11]2 years ago
4 0

A parallelogram is a figure which has its <em>opposite</em> sides to be <u>equal</u> and <u>parallel</u>. The <em>missing</em> reason in the proof is:

B. Substitution Angle Angle Postulate.

A <em>parallelogram</em> is a type of quadrilateral that has its <u>opposite</u> sides to be equal and parallel. The sum of its <em>internal</em> angles is 360^{o}.

To <u>prove</u> that ∠ BAD ≅ ∠ DCB, we have:

Given parallelogram ABCD;

<BAC ≅ <ACD (alternate angle theorem)

<DAC ≅ <ACB (alternate angle theorem)

<BAC + <DAC = <BAD

Also,

<BCA + <DCA = <BCD

Therefore,

<BAD ≅ <DCB (Substitution Angle Angle Postulate)

Thus, the <u>missing</u> reason in the partial proof is:

option B. Substitution Angle Angle Postulate

A sketch is attached to this question for more clarifications.

Visit: brainly.com/question/3100335

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F(x)=4^x and g(x)=4^x+2
dsp73

Given:

The two functions are:

f(x)=4^x

g(x)=4^x+2

To find:

The type of transformation from f(x) to g(x) in the problem above and including its distance moved.

Solution:

The transformation is defined as

g(x)=f(x+a)+b                .... (i)

Where, a is horizontal shift and b is vertical shift.  

  • If a>0, then the graph shifts a units left.
  • If a<0, then the graph shifts a units right.
  • If b>0, then the graph shifts b units up.
  • If b<0, then the graph shifts b units down.

We have,

f(x)=4^x

g(x)=4^x+2

The function g(x) can be written as

g(x)=f(x)+2            ...(ii)

On comparing (i) and (ii), we get

a=0,b=2

Therefore, the type of transformation is translation and the graph of f(x) shifts 2 units up to get the graph of g(x).

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3 years ago
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LUCKY_DIMON [66]

Answer:

=8\sqrt{15}b^{\frac{7}{2}}

Step-by-step explanation:

\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}

=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}

=\sqrt{40}b^2\sqrt{24b^3}

\sqrt{24b^3}

=\sqrt{24}\sqrt{b^3}

=\sqrt{24}b^{\frac{3}{2}}

=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2

=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

\sqrt{2^3}

=2^{3\cdot \frac{1}{2}

=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2

=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2

=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}

2^{\frac{3}{2}+\frac{3}{2}}

=2^3

=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}

b^{\frac{3}{2}+2}

=b^{\frac{7}{2}}

=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}

=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}

=8\sqrt{15}b^{\frac{7}{2}}

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Travis and Wendy were in an election for club president. Of the club members, 1/3 voted for Travis, 5/12 voted for Wendy, and th
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