To get the answer to this problem you first factor out the common term 2
(n+3)/(2(n-3) ) * (n+3)/(3n-9)
then factor out the common term 3
(n+3)/(2 (n-3) ) * (n+3)/(3 (n-3) )
then simplify
( (n+3)(n+3)/(2 (n-3)*3(n-3) )
Use product rule : x^a x^b= x^a+b
( (n+3)^2/(2 (n-3)*3(n-3) )
simplify 2 (n-3) * 3(n-3) to 6(n-3)(n-3)
( (n+3)^2/(6 (n-3)(n-3) )
use product rule again : x^a x^b=x^a+b
so you get the answer : ( (n+3)^2)/(6 (n-3)^2 )
so the orrect answer to this problem is answer choice (C)
Answer:
Brett, Riley, Ellema, Jennifer, Kamal, Felipe
Step-by-step explanation:
You have put their scores least to greatest, -7<-5<-1<0<1<2<3
You will have 2 apples less.
The formula is
A=p (1+r/k)^kt
A future value 10000
P present value 6000
R interest rate 0.0375
K compounded every two months 6
T time?
We need to solve for t
T= [log (A/p)÷log (1+r/k)]÷k
T=(log(10,000÷6,000)÷log(1+0.0375÷6))÷6
T=13.7 years
Round your answer to get
T=14 years