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3 years ago

2 x (3^3-5+8) pemdas

Mathematics

1 answer:

Pavel [41]3 years ago

6 0

Answer:

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

Step 1: Define Expression

2 × (3³ - 5 + 8)

Step 2: Evaluate

[Parenthesis] Exponents: 2 × (27 - 5 + 8)
[Parenthesis] Subtract: 2 × (22 + 8)
[Parenthesis] Add: 2 × 30
Multiplication: 60

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Step-by-step explanation:

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3 years ago

Before a computer is assembled, its motherboard goes through a special inspection. Assume only 85% of motherboards pass this ins

andreyandreev [35.5K]

Answer:

(a) The probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b) On average, 1.18 motherboards should be inspected until a motherboard that passes inspection is found.

Step-by-step explanation:

Let X = number of motherboards that pass the inspection.

The probability that a motherboards pass the inspection is P (X) = p = 0.85.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of X is,

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...$

(a)

Compute the probability that at least 13 of the next 15 motherboards pass inspection as follows:

P (X ≥ 13) = P (X= 13) + P (X = 14) + P (x = 15)

$={15\choose 13}0.85^{13}(1-0.85)^{15-13}+{15\choose 13}0.85^{14}(1-0.85)^{15-14}\\+{15\choose 13}0.85^{16}(1-0.85)^{15-15}\\=0.2856+0.2312+0.0874\\=0.6042$

Thus, the probability that at least 13 of the next 15 motherboards pass inspection is 0.6042.

(b)

Computed the expected number of motherboards should be inspected until a motherboard that passes inspection is found as follows:

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4 years ago

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$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

Volume of cone will be ~

$\fbox \colorbox{black}{ \colorbox{white}{volume} \: \: \: \: \: \colorbox{white}{=} \: \: \: + \colorbox{white}{462 \: cm³ }}$

$\large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}$

Let's find the volume of cone with ~

radius (r) = 7 cm

height (h) = 9 cm

And as we know, volume of cone is equal to ~

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now, let's plug in the values and find the volume ~

$\dfrac{1}{ \cancel{3} }\times \dfrac{22}{\cancel{7}} \times \cancel{7 }\times 7 \times \cancel{9}$

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3 years ago

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Part C:

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Part D:

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1 year ago