All categories

2 years ago

64^1/2 divided by 10^-2

Mathematics

1 answer:

tresset_1 [31]2 years ago

5 0

Answer:

800

Step-by-step explanation: I have the question before and got it right

You might be interested in

(-1+2p)(3-4p) Answer should be in polynomial standard form.

noname [10]

Answer:

-8 $p^{2}$ +10p-3

Step-by-step explanation:

7 0

4 years ago

The angle measures associated with which set of ordered pairs share the same reference angle? (Negative StartFraction StartRoot

Katarina [22]

Answer:

$(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

Step-by-step explanation:

The reference angle is the angle that the given angle makes with the x-axis.

For an ordered pair to share the same reference angle, the x and y coordinates must be the same or a factor of each other.

From the given options:

$(A)\left(-\dfrac{\sqrt{3} }{2} ,-\dfrac{1 }{2}\right)$ and \left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)\\\\(B)\left(\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(-\dfrac{\sqrt{3} }{2}, \dfrac{1 }{2}\right)\\\\(C)\left(-\dfrac{1 }{2},-\dfrac{\sqrt{3} }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)\\\\(D)\left(\dfrac{\sqrt{3} }{2},\dfrac{1 }{2} \right)$ and \left(\dfrac{1 }{2},\dfrac{\sqrt{3} }{2} \right)$

We observe that only the pair in option C has the same x and y coordinate with the second set of points being a negative factor of the first term. Therefore, they have the same reference angle.

5 0

3 years ago

Read 2 more answers

Find the value of 3 ÷ (9-6) + 4×2

34kurt

Answer:

Step-by-step explanation:

Use the order of operations to solve this (PEMDAS or GEMDAS)

Hope this helps!

~Courtney

7 0

3 years ago

Read 2 more answers

One eighth of a number increased by 20 is 32

Anon25 [30]

1/8x-20=32
1/8x=32+20
1/8x=52
X=52*8

4 0

3 years ago

Read 2 more answers

52.5 ft 25 ft 22 ft 18.18 ft for the picture below

Ugo [173]

Answer:

18.1818181 Feet

Step-by-step explanation:

Divide 27.5 by 20 to establish a ratio between the length and width of the house, then multiply your new ratio by 25. Units do not matter, as long as it's not like 27.5 mm high by .05 ft wide.

6 0

3 years ago