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2 years ago

7

20= -x + (x squared) solve for x

2 answers:

Sauron [17]2 years ago

4 0

Here is your answer:

x=5

x=-4

MArishka [77]2 years ago

3 0

Answer:

Step-by-step explanation:

x = 5

x= -4

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Write a paragraph or two column proof.

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3 years ago

Hey!! can someone please help me with these math problems? I would appreciate it, thank you(:

marissa [1.9K]

{x=-1/3-10/3y

5x+20y=5

5(-1/3-10/3y)+20y=5

solve the equation

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Y=5

substitute the value of y into the equation

x=-1/3-10/3×2

.solve the equation

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.x=-7

(x,y)=(-7,2)

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3 years ago

Read 2 more answers

9. On a game show, there are 16 questions: 8 easy, 5 medium-hard, and 3 hard. If contestants are given questions

just olya [345]

Answer:

$\frac{7}{30}\approx0.23$

Step-by-step explanation:

Given:

Number of questions (N) = 16

Number of easy questions (E) = 8

Number of medium-hard questions (M) = 5

Number of hard questions (H) = 3

Now, the probability of getting the first question as easy question is given as:

$P(E1)=\frac{\textrm{Number of easy questions}}{\textrm{Total questions}}\\\\P(E1)=\frac{E}{N}=\frac{8}{16}=0.5$

Now, probability of getting the second question as easy question is given as:

$P(E2)=\frac{\textrm{Number of easy questions left}}{\textrm{Total questions left}}\\\\P(E2)=\frac{E-1}{N-1}=\frac{7}{15}$

Now, probability that the first two contestants will get easy questions is given by the product of $P(E1)\ and\ P(E2)$ . So,

$P(2\ easy\ questions)=P(E1)\times P(E2)\\\\P(2\ easy\ questions)=\frac{1}{2}\times \frac{7}{15}\\\\P(2\ easy\ questions)=\frac{7}{30}\approx 0.23$

Therefore, the probability that the first two contestants will get easy questions is $\frac{7}{30}\approx0.23$

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3 years ago

A rectangle is 1/2 ft long and 3/4 ft wide.

koban [17]

0.38 or 3/8

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3 years ago

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The average age for licensed drivers in a certain county is 42.6 years with a standard deviation of 12.2 years. A researcher obt

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3 years ago