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2 years ago

7

Will use us 3/4 cup of olive oil to make three batches of salad dressing how much oil does will use for one batch of salad dress

ing

2 answers:

ch4aika [34]2 years ago

8 0

1/4 cup of olive oil for one batch of salad dressing.

Likurg_2 [28]2 years ago

6 0

Simple 3/4 for 3 so divide 3/4 by 3 = 3/4 x 1/3 = 1/4 for each batch

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Which three of the following sets of angle measures could represent the measures of the angles of a triangle?

slamgirl [31]

To figure this out we keep in mind two rules

1. A triangles sum of angles is 180

2. An angle of a triangle can not be 0

So the answer is the following

2, 3 & 4

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2 years ago

According to the Ruler Postulate, what does the set of points on any line correspond to?

Brrunno [24]

Answer:

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Step-by-step explanation:

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2 years ago

A cube has a surface area of 54 square centimeters.

umka21 [38]

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Step-by-step explanation:

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1 year ago

Read 2 more answers

Lines k and n intersect on the y-axis

avanturin [10]

a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

m is the slope, which is the rate of change.
b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

In which $m_1$ and $m_2$ are the slopes of <u>k and m.</u>

Line k goes through points (-3,-1) and (5,2), thus, it's slope is:

$m_1 = \frac{2 - (-1)}{5 - (-3)} = \frac{3}{8}$

The tangent of 109 degrees is $\tan{109^{\circ}} = -\frac{29}{10}$
Thus, the slope of line m is found solving the following equation:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

$-\frac{29}{10} = \frac{m_2 - \frac{3}{8}}{1 + \frac{3}{8}m_2}$

$m_2 - \frac{3}{8} = -\frac{29}{10} - \frac{87}{80}m_2$

$m_2 + \frac{87}{80}m_2 = -\frac{29}{10} + \frac{3}{8}$

$\frac{167m_2}{80} = \frac{-202}{80}$

$m_2 = -\frac{202}{167}$

Thus:

$y = -\frac{202}{167}x + b$

It goes through point (-2,6), that is, when $x = -2, y = 6$ , and this is used to find b.

$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

Thus. the equation of line k, in slope-intercept formula, is:

$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

Lines j and k intersect at an angle of 90º, thus they are perpendicular, which means that the multiplication of their slopes is -1.

Thus, the slope of line j is:

$-\frac{202}{167}m = -1$

$m = \frac{167}{202}$

Then

$y = \frac{167}{202}x + b$

Also goes through point (-2,6), thus:

$6 = \frac{167}{202}(-2) + b$

$b = \frac{(2)167 + 202(6)}{202}$

$b = \frac{1546}{202}$

The equation of line j is:

$y = \frac{167}{202}x + \frac{1546}{202}$

A similar problem is given at brainly.com/question/16302622

7 0

2 years ago

Which of the following expressions are equivalent to \left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}(9 87 +2 54 )− 21

lora16 [44]

Answer:

$12\dfrac{7}{40}$

Step-by-step explanation:

The given expression is

$\left(9\dfrac{7}{8} + 2\dfrac{4}{5}\right)-\dfrac{1}{2}$

We need to find the simplified form of the given expression.

It can be rewritten as

$\left(9+\dfrac{7}{8} + 2+\dfrac{4}{5}\right)-\dfrac{1}{2}$

Combine integers and fractions separately.

$(9+2)+(\dfrac{7}{8}+\dfrac{4}{5}-\dfrac{1}{2})$

Taking LCM we get

$11+\dfrac{35+32-20}{40}$

$11+\dfrac{47}{40}$

In can be written as

$11+\dfrac{40+7}{40}$

$11+1+\dfrac{7}{40}$

$12+\dfrac{7}{40}$

$12\dfrac{7}{40}$

Therefore, the expression $12\dfrac{7}{40}$ is equivalent to the given expression.

5 0

2 years ago