What is the answer to this problem?
1 answer:
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Answer:
Solving the given linear system, we get x = 1 and y = -3.
The solution set is: (1,-3)
Step-by-step explanation:
We need to solve the linear system of equations.
We can write second equation y=x-4 as:
Let:
Now, Adding equation 1 and 2
So, we get x = 1
Now, put value of x in second equation to find value of y:
So, we get y = -3
Solving the given linear system, we get x = 1 and y = -3.
The solution set is: (1,-3)
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Answer:
x^2 -4x +2 = 0
Step-by-step explanation:
The other root is the conjugate of the given one, so is 2-√2. The quadratic equation in factored form is then ...
(x -2-√2)(x -2+√2) = 0
Expanding this, we get ...
(x -2)^2 -(√2)^2 = 0
x^2 -4x +4 -2 = 0
x^2 -4x +2 = 0 . . . . the equation you're looking for
