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3 years ago

YO PLEASE HELP AS SOON AS POSSIBLE!!! MARKIN BRAINIEST!!!

Mathematics

1 answer:

Elden [556K]3 years ago

7 0

√2 • √2 = 2
√5 • √7 = √35
√2 •√18 = √2 • 3√2 = 3(2) = 6
√2 • √6 = √12 = 2√3

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Evaluate the surface integral. s (x + y + z) ds, s is the parallelogram with parametric equations x = u + v, y = u − v, z = 1 +

Stolb23 [73]

$S$ is given to be parameterized by

$\mathbf r(u,v)=\langle x(u,v),y(u,v),z(u,v)\rangle=\langle u+v,u-v,1+2u+v\rangle$

with $0\le u\le3$ and $0\le v\le2$ . We have

$\mathbf r_u=\langle1,1,2\rangle$
$\mathbf r_v=\langle1,-1,1\rangle$
$\mathbf r_u\times\mathbf r_v=\langle3,1,-2\rangle$
$\left\|\mathbf r_u\times\mathbf r_v\right\|=\sqrt{14}$

The surface integral is then

$\displaystyle\iint_S(x+y+z)\,\mathrm dS=\iint_S(x(u,v)+y(u,v)+z(u,v))\left\|\mathbf r_u\times\mathbf r_v\right\|\,\mathrm du\,\mathrm dv$
$=\displaystyle\sqrt{14}\int_{u=0}^{u=3}\int_{v=0}^{v=2}((u+v)+(u-v)+(1+2u+v))\,\mathrm dv\,\mathrm du$
$=\displaystyle\sqrt{14}\int_{u=0}^{u=3}\int_{v=0}^{v=2}(4u+v+1)\,\mathrm dv\,\mathrm du$
$=\displaystyle\sqrt{14}\left(8\int_{u=0}^{u=3}u\,\mathrm du+3\int_{v=0}^{v=2}v\,\mathrm dv+6\right)$
$=\displaystyle\sqrt{14}\left(8\int_{u=0}^{u=3}u\,\mathrm du+3\int_{v=0}^{v=2}v\,\mathrm dv+6\right)$
$=48\sqrt{14}$

4 0

4 years ago

Solve the equation then check your solution 5p=140 A)28 B)700 C)-28 D)26

Kruka [31]

Answer:

p=28

Step-by-step explanation:

5p=140

To to find the value of p divide both sides by 5 (5p/5 and 140/5)

p=28!

4 0

3 years ago

Read 2 more answers

Suppose a baseball team has 14 players on the roster who are not members of the pitching staff. Of those 14 players, assume that

Nadusha1986 [10]

Answer: Our required probability would be 0.70.

Step-by-step explanation:

Since we have given that

Number of players = 14

Number of players have recently taken a performance enhancing drug = 3

Number of players have not recently taken a performance enhancing drug = 14-3=11

Number of members chosen randomly = 5

We need to find the probability that at least one of the tested players is found to have taken a performance enhancing drug.

P(Atleast 1) = 1 - P(none is found to have taken a performance enhancing drug)

So, P(X≥1)=1-P(X=0)

$P(X\geq 1)=1-^5C_0(\dfrac{11}{14})^5\\\\P(X\geq 1)=1-(0.786)^5\\\\P(X\geq 1)=0.70$

Hence, our required probability would be 0.70.

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3 years ago

Find the mean. Z-score = -1.4 Standard Deviation: 7 x = 20

Umnica [9.8K]

Answer:

9.6

Step-by-step explanation:

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3 years ago

Evaluate: g(x) = 3•2^x+2 + 3 g(3)

sertanlavr [38]

If the 3 is supposed to be replaced by any x's, then the answer would be 29 I believe.

4 0

3 years ago