Both variables (x) are 3.
4×3=12
12-2=10
16×3=48
48-8=40
3 fits the variable of the missing number.
4x-2+1=3x+5
Subtract 3x from both sides
x-2+1=5
Same as
x-1=5
Add 1 to both sides
x=6
Answer:
4.F(x) > 0 over the intervals (-0.7, 0.76) and (0.76, ∞).
Step-by-step explanation:
<span><span>Make it a solid line for y≤ or y≥, and a dashed line for y< or y>
</span><span>Shade above the line for a "greater than" (y> or y≥)
or below the line for a "less than" (y< or y≤).
So, the answer is A) </span></span><span>x + 4y ≥ −4
</span><span>x + 4y ≥ −4
4y </span>≥ -x - 4
y ≥ -x/4 - 1
