Answer:
P(5 ≤ X ≤ 8) = a rectangle with a width of 3 and height of .15 = 3(.15) = .45
P( 4 ≤ X ≤ 5) = a triangle with a base of 1 and a height of (0.15 -0.05) = .10
So....this area = (1/2)(1)(.10) = .05
And another rectangle with a width of 1 and height of .05 = (1) (.05) = .05
So
Adding these areas
P( 4 ≤ X ≤ 8 ) = .45 + .05 + .05 = .55
Step-by-step explanation:
Hoped this helped!
Answer: 5x + 2y = 8 = x=-2/5y+8/5
y = 3x - 7= x= 1/3y+7/3
Step-by-step explanation:
<h3>given:</h3>
radius= 4 m
<h3>to find:</h3>
the volume of the given sphere.
<h3>solution:</h3>




<u>therefore</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>sphere</u><u> </u><u>is</u><u> </u><u>267.95</u><u> </u><u>cubic</u><u> </u><u>meters</u><u>.</u>
It depends on how much the computer game costs.
Answer: a. 0.61
b. 0.37
c. 0.63
Step-by-step explanation:
From the question,
P(A) = 0.39 and P(B) = 0.24
P(success) + P( failure) = 1
A) What is the probability that the component does not fail the test?
Since A is the event that the component fails a particular test, the probability that the component does not fail the test will be P(success). This will be:
= 1 - P(A)
= 1 - 0.39
= 0.61
B) What is the probability that a component works perfectly well (i.e., neither displays strain nor fails the test)?
This will be the probability that the component does not fail the test minus the event that the component displays strain but does not actually fail. This will be:
= [1 - P(A)] - P(B)
= 0.61 - 0.24
= 0.37
C) What is the probability that the component either fails or shows strain in the test?
This will simply be:
= 1 - P(probability that a component works perfectly well)
= 1 - 0.37
= 0.63