Como se faz o cálculo 13÷5,2

Mathematics

2 answers:

Sonja [21]3 years ago

8 0

a resposta para a sua pergunta é 2.5 esperança que ajuda por favor marcar como mais inteligente se correto obrigado

pogonyaev3 years ago

6 0

Answer: 26/5

Step-by-step explanation:

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I’m confused please help

Maru [420]

<h2>Hello!</h2>

The answer is:

$Sin(A)=0.93$

To solve the problem, remember to set your calculator in "degree mode"

So, we are given that the angle A is equal to 68°

So, we have that:

$Sin(A)=Sin(68\°)=0.93$

Hence, we have that:

$Sin(A)=0.93$

Have a nice day!

4 0

3 years ago

Nikolas calculated the volume of the prism. His work is shown below. A triangular prism. The triangular base has a base of 5.8 f

Brut [27]

Answer:

B he used the incorrect formula for the volume of the prism

3 0

3 years ago

Read 2 more answers

Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$