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2 years ago

Help mee please!! i need to pass

Mathematics

2 answers:

Zolol [24]2 years ago

5 0

Answer:

Step-by-step explanation:

weeeeeb [17]2 years ago

5 0

Answer:

Arc length = 20π in.

Step-by-step explanation:

To find the length of an arc, we can use the following formula:

$\boxed{s = r \theta}$

where:

s = arc length (? in.)

r = radius of circle (24 in.)

θ = central angle ( $\bf \frac{5 \pi}{6}$ radians)

Substituting the values into the formula:
$S = 24 \times \frac{5 \pi}{6}$

= 20π in.

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Evaluate the polynomial function p (x) = 2x4 - 3x2 + x - 1 to find p (-1).

Alisiya [41]

$p(x)=2x^4-3x^2+x-1\\\\
Substitude\ p=-1\ into\ equation\\\\
p(-1)=2x^4-3x^2+x-1=2*(-1)^4-3(-1)^2-1-1=\\2*1-3*1-2=2-3-2=-3\\Answer\ p(-1)=-3$

7 0

3 years ago

Radioactive Decay:

Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

Answer: The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

Step-by-step explanation:

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

$k=\frac{0.693}{t_{1/2}}$

where,

$t_{1/2}$ = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

$k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}$

The formula used to calculate the time period for a first order reaction follows:

$t=\frac{2.303}{k}\log \frac{a}{(a-x)}$

where,

k = rate constant = $0.01506days^{-1}$

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

$t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days$

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0

3 years ago

In the diagram below what is the approximate length of the minor arc XY

sveta [45]

C = 2pi r= 2 (3.14) (27) = 169.56

Let XY = x

169.56 / 360 = x / 60

360x = 169.56 * 60

360x = 10173.60

x = 28.26

x = 28.3

Answer is C. 28.3 cm

5 0

3 years ago

Read 2 more answers

0.15(y-0.2)=2-0.5(1-y) The answer is -153/35 I just need to know how to get that

butalik [34]

Answer:

$y=-\dfrac{153}{35}$ .

Step-by-step explanation:

The given equation is

$0.15(y-0.2)=2-0.5(1-y)$

Using distributive property, we get

$0.15(y)+0.15(-0.2)=2-0.5(1)-0.5(-y)$

$0.15y-0.03=2-0.5+0.5y$

$0.15y-0.03=1.5+0.5y$

Isolate variable terms.

$0.15y-0.5y=1.5+0.03$

$-0.35y=1.53$

Divide both sides by -0.35.

$y=\dfrac{1.53}{-0.35}$

$y=-\dfrac{1.53}{0.35}\times \dfrac{100}{100}$

$y=-\dfrac{153}{35}$

Therefore, $y=-\dfrac{153}{35}$ .

6 0

3 years ago

I need help proving the y-intercept is 5 but I can't figure it out and will give brainliest if you can show the steps how you go

elixir [45]

So, honestly if its allowed you can just graph the equation ti prove the y intercept is five

4 0

3 years ago