Answer:
![52+12\pi](https://tex.z-dn.net/?f=52%2B12%5Cpi)
Step-by-step explanation:
The diagram for the question is attached below
perimeter of the triangle is 28 feet
area of a square is 144 feet
Area of the square is side^2
![side ^2= 144](https://tex.z-dn.net/?f=side%20%5E2%3D%20144)
take square root on both sides
side = 12
side of the square = 12
side is the diameter of the semicircle
Diameter = 12 , so radius = 12 divide 2 = 6
circumference of semicircle = ![2\pi r=2\pi (6)=12\pi](https://tex.z-dn.net/?f=2%5Cpi%20r%3D2%5Cpi%20%286%29%3D12%5Cpi)
one side of the rectangle is calculated in the perimeter of triangle and other side is calculated using circumference
perimeter of other two side = 2(12)= 24
Total perimeter = ![28+24+12\pi =52+12\pi](https://tex.z-dn.net/?f=28%2B24%2B12%5Cpi%20%3D52%2B12%5Cpi)
.70 * x = 9.1
.70/.70 * x = 9.1/.70
x = 13
Answer:Do you have a pic of the map? It would make it easier to solve if I could see the map. Its basic area. A=base times height. If the park is 50 m long and is a square, you would do 50 times 50=2500
tep-by-step explanation: