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ExtremeBDS [4]
3 years ago
9

Express each rational number as a fraction or mixed number in simplest form.

id="TexFormula1" title="\sqrt{25}" alt="\sqrt{25}" align="absmiddle" class="latex-formula">
Mathematics
2 answers:
siniylev [52]3 years ago
6 0

Answer:

\sqrt{25} In its simplist form is 5.

Step-by-step explanation:

Anna [14]3 years ago
6 0

Answer: 5/1

Step-by-step explanation:

correct on edgenuity

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A camp counselor is trying to determine, of the places they have previously camped, where his campers’ favorite camping spots ar
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you need to send a picture of the table

Step-by-step explanation:

No one can help without the numbers.

6 0
2 years ago
The selling price of an item is ​$480. It is marked down by ​10%, but this sale price is still marked up from the cost of ​$. Fi
erma4kov [3.2K]

Answer:

Markup = [(Revenue – COGS) / COGS] X 100.

Markup = (Gross Profit / COGS) X 100.

Markup = [(Revenue – COGS) / COGS] X 100.

Markup = [($400 – $250) / $250] X 100.

Selling Price = [(Markup X COGS) + COGS] X 100.

Selling Price = (Markup X COGS) + COGS.

Selling Price = (0.50 X $100) + $100.

Step-by-step explanation:

um i think this is the answer

4 0
3 years ago
Read 2 more answers
A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
KIM [24]

Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

Then, if we calculate every probability using eq. 1, we get:

P(x ≤ 4) = 0.000044 + 0.000445 + 0.002235 + 0.007479 + 0.018765

P(x ≤ 4) = 0.028968

Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

3 0
3 years ago
Trevor took one of his friends out to lunch. The lunches cost $248.40 and he paid 12.5% sales tax. If Trevor left a 15% tip on t
bixtya [17]
He paid ...

-- The cost of the lunches      (100%  =  1.00 of it)    

-- 15% of the cost as a tip    (15%  =  0.15 of it)

-- 12% of the cost as sales tax  (12%  =  0.12 of it)

Total that he paid = (1.00 + 0.15 + 0.12)  =  1.27 of $248.40

                                                           =      $315.47   .

Trevor is one generous guy !
4 0
3 years ago
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