Answer:
z =23
Step-by-step explanation:
The three angles in a triangle add to 180 degrees.
62+95+z = 180
Combine like terms
157 +z = 180
Subtract 157 from each side
157-157 +z = 180-157
z =23
Answer: 16 double rooms and 10 single rooms were rented.
Step-by-step explanation:
Let x represent the number of double rooms that were rented.
Let y represent the number of single rooms that were rented.
The total number of rooms rented in a day is 26. It means that
x + y = 26
A motel rents double rooms at $34 per day and single rooms at $26 per day. If all the rooms that were rented for one day cost a total of $804, it means that
34x + 26y = 804 - - - - - - - - - - -1
Substituting x = 26 - y into equation 1, it becomes
34(26 - y) + 26y = 804
884 - 34y + 26y = 804
- 34y + 26y = 804 - 884
- 8y = - 80
y = - 80/ - 8 = 10
x = 26 - y = 26 - 10
x = 16
Yes! This is because -150/10 can be simplified to be -15, which is a rational number.
The word “rational” sounds like another math word you’ve heard of before. Do you know what it is?
Well, it’s “ratio”!! Ratios can be seen in the forms x:y and x/y.
ANY RATIONAL NUMBER HAS THE ABILITY TO BE WRITTEN AS A RATIO!! This will completely exclude numbers with super long decimal points (ex: 1.2345678809928374737272828...)
This number also meets the requirements of being an integer. An integer is any whole number (this excludes decimals and fractions)
I know it’s written as a fraction. However, the fraction could be simplified, making it -15, which means this is both a rational number and an integer!!
5)
a. The equation that describes the forces which act in the x-direction:
<span> Fx = 200 * cos 30 </span>
<span>
b. The equation which describes the forces which act in the y-direction: </span>
<span> Fy = 200 * sin 30 </span>
<span>c. The x and y components of the force of tension: </span>
<span> Tx = Fx = 200 * cos 30 </span>
<span> Ty = Fy = 200 * sin 30 </span>
d.<span>Since desk does not budge, </span><span>frictional force = Fx
= 200 * cos 30 </span>
<span> Normal force </span><span>= 50 * g - Fy
= 50 g - 200 * sin 30
</span>____________________________________________________________
6)<span> Let F_net = 0</span>
a. The equation that describes the forces which act in the x-direction:
(200N)cos(30) - F_s = 0
b. The equation that describes the forces which act in the y-direction:
F_N - (200N)sin(30) - mg = 0
c. The values of friction and normal forces will be:
Friction force= (200N)cos(30),
The Normal force is not 490N in either case...
Case 1 (pulling up)
F_N = mg - (200N)sin(30) = 50g - 100N = 390N
Case 2 (pushing down)
F_N = mg + (200N)sin(30) = 50g + 100N = 590N
Answer:
<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>
Step-by-step explanation:
