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ira [324]
3 years ago
13

What are the x intercepts for 5/x + 1/3x = 4x/3

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
4 0
\bf \cfrac{5}{x}+\cfrac{1}{3}x=\cfrac{4x}{3}\implies \cfrac{5}{x}+\cfrac{x}{3}=\cfrac{4x}{3}

now, the cheap answer will be, let's just get the LCD of all those fractions, hmm let's see is 3x, and multiply all the fractions by the LCD, that way, getting rid of the denominators.

\bf \cfrac{5}{x}+\cfrac{1}{3}x=\cfrac{4x}{3}\implies \cfrac{5}{x}+\cfrac{x}{3}=\cfrac{4x}{3}\impliedby \times \stackrel{LCD}{3x}
\\\\\\
\boxed{3x}\cdot \cfrac{5}{x}+\boxed{3x}\cdot \cfrac{x}{3}=\boxed{3x}\cdot \cfrac{4x}{3}\implies 15+x^2=4x^2\implies 15=3x^2
\\\\\\
\cfrac{15}{3}=x^2\implies 5=x^2\implies \pm\sqrt{5}=x
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Someone help me please
galben [10]

Answer:

∛27 = 3

Step-by-step explanation:

A radical is simply a fractional exponent: a^{(\frac{m}{n})} = \sqrt[n]{a^{m} }

Hence, ∛27 = 27^{(\frac{1}{3})}

Since 27 = 3³, then:

You could rewrite ∛27 as ∛(3)³.

\sqrt[3]{3^{(3)} } = 3^{[(3)*(\frac{1}{3})]}

Multiplying the fractional exponents (3 × 1/3) will result in 1 (because 3 is the <u><em>multiplicative inverse</em></u> of 1/3). The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product as 1.

Therefore, ∛27 = 3.

3 0
3 years ago
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How do I factor 6x^2+17x+5=0
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Split the second term in 6x^2 + 17x + 5 into two terms

6x^2 + 15x + 2x + 5 = 0

Factor out common terms in the first two terms, then in the last two terms.

3x(2x + 5) + (2x + 5) = 0

Factor out the common term 2x + 5

(2x + 5)(3x + 1) = 0

Solve for x

<u>x = -5/2, -1/3</u>

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3 years ago
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3 years ago
What is...<br><br> 7 4/7 + 14 4/5<br> Thank you so much!
SCORPION-xisa [38]
7+4/7+14+4/5
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Answer:

3

Step-by-step explanation:

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