What are the x intercepts for 5/x + 1/3x = 4x/3

1 answer:

4 0

$\bf \cfrac{5}{x}+\cfrac{1}{3}x=\cfrac{4x}{3}\implies \cfrac{5}{x}+\cfrac{x}{3}=\cfrac{4x}{3}$

now, the cheap answer will be, let's just get the LCD of all those fractions, hmm let's see is 3x, and multiply all the fractions by the LCD, that way, getting rid of the denominators.

$\bf \cfrac{5}{x}+\cfrac{1}{3}x=\cfrac{4x}{3}\implies \cfrac{5}{x}+\cfrac{x}{3}=\cfrac{4x}{3}\impliedby \times \stackrel{LCD}{3x}
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\boxed{3x}\cdot \cfrac{5}{x}+\boxed{3x}\cdot \cfrac{x}{3}=\boxed{3x}\cdot \cfrac{4x}{3}\implies 15+x^2=4x^2\implies 15=3x^2
\\\\\\
\cfrac{15}{3}=x^2\implies 5=x^2\implies \pm\sqrt{5}=x$

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Someone help me please

galben [10]

Answer:

∛27 = 3

Step-by-step explanation:

A radical is simply a fractional exponent: $a^{(\frac{m}{n})} = \sqrt[n]{a^{m} }$

Hence, ∛27 = $27^{(\frac{1}{3})}$

Since 27 = 3³, then:

You could rewrite ∛27 as ∛(3)³.

$\sqrt[3]{3^{(3)} } = 3^{[(3)*(\frac{1}{3})]}$

Multiplying the fractional exponents (3 × 1/3) will result in 1 (because 3 is the multiplicative inverse of 1/3). The multiplicative inverse of a number is defined as a number which when multiplied by the original number gives the product as 1.

Therefore, ∛27 = 3.

3 0

3 years ago

Read 2 more answers

How do I factor 6x^2+17x+5=0

Sergio [31]

Split the second term in 6x^2 + 17x + 5 into two terms

6x^2 + 15x + 2x + 5 = 0

Factor out common terms in the first two terms, then in the last two terms.

3x(2x + 5) + (2x + 5) = 0

Factor out the common term 2x + 5

(2x + 5)(3x + 1) = 0