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xeze [42]
3 years ago
13

Simplify x • x squared 6

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
6 0
Hi there!

\textbf{PRODUCT\: RULE} :-

It tells us that, When multiplying two powers that have the same base, you can add the exponents. 

Then,
According to th' question :-

x + x⁶

⇒ x¹ + x⁶

⇒ x¹ ⁺ ⁶

⇒ x⁷

Hence,
The required answer is x⁷


~ Hope it helps!
posledela3 years ago
3 0

<u>Answer</u>

\boxed {x^{7}}


<u>Detailed Explanation and Solution </u>

You would only need to combine like terms in this problem. 


x^{1}+x^{6}


Therefore, the answer would be \boxed {x^{7}}

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A car is driven 440 miles in 11 hours. What is the rate in miles per hour?
nikklg [1K]

Answer:

40 Mph

Step-by-step explanation:

440/11 is equal to 40

5 0
3 years ago
Read 2 more answers
Y=5x-4
anyanavicka [17]

Answer:

\displaystyle -5x + y = -92\:or\:y = 5x - 92

Step-by-step explanation:

−12 = 5[16] + b

80

\displaystyle -92 = b \\ \\ y = 5x - 92

If you want it in <em>Standard</em><em> </em><em>Form</em>:

y = 5x - 92

- 5x - 5x

__________

\displaystyle -5x + y = -92

I am joyous to assist you anytime.

7 0
3 years ago
How do you do this ? Please step by step explanation due tom
inna [77]

Answer: C im pretty sure

Step-by-step explanation:

Use this link it explains it pretty well

https://www.calculatorsoup.com/calculators/math/mixednumbers.php

Just copy and paste the link

6 0
3 years ago
83 random samples were selected from a normally distributed population and were found to have a mean of 32.1 and a standard devi
arlik [135]

Answer:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

Step-by-step explanation:

Information given

\bar X=32.1 represent the sample mean

\mu population mean (variable of interest)

s=2.4 represent the sample standard deviation

n=83 represent the sample size  

Confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The degrees of freedom given by:

df=n-1=8-1=7

The confidence level is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,82)" "=CHISQ.INV(0.95,82)". so for this case the critical values are:

\chi^2_{\alpha/2}=104.139

\chi^2_{1- \alpha/2}=62.132

The confidence interval is given by:

\frac{(82)(2.4)^2}{104.139} \leq \sigma^2 \leq \frac{(82)(2.4)^2}{62.132}

4.525 \leq \sigma^2 \leq 7.602

Now we just take square root on both sides of the interval and we got:

2.127 \leq \sigma \leq 2.757

5 0
3 years ago
How should they divide the money so that each class gets the same fraction of the prize money as the fraction of the box tops th
bija089 [108]

Figure the fraction of box tops each class collected, then multiply the prize money by that fraction.

Total box tops = 3760 +2301 +1855 = 7916

Mr Coronado's class's fraction: 3760/7916 × $600 = $284.99

Mrs De Souza's class's fraction: 2301/7916 × $600 = $174.41

Mr Nost's class's fraction: 1855/7916 × $600 = $140.60

5 0
3 years ago
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