Their both the answer hope this helps
for all of them its base times height
v=bh
1) (8*6/2)*9.5=228
2) (4.5/2)^2 *8= 40.5
3) (3.3* 8.3/2) *5.4= 74.0
4) ((3.2+4.8)/2)* 2.7 *4.4= 47.5
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Answer:
8. C) 24.2
9. A) 8.1
Step-by-step explanation:
8. The radius is shown as being 7.8 +4.3 = 12.1, so the diameter x is ...
d = 2r
x = 2(12.1) = 24.2
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9. The unknown leg (y) of the right triangle can be found from the Pythagorean theorem.
y² +11.7² = 12.5² . . . . . the radius is half the diameter
y = √(156.25 -136.89) = √19.36 = 4.4
Then the segment of interest is ...
x + y = 12.5
x = 12.5 -4.4 = 8.1
Answer:
use this m a t h w a y it will help you i promise
Step-by-step explanation:
Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that
<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>
<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>
where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.
Then the sum is
<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>
and its magnitude is
||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)
… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))
… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))
… = √(16 + 16 cos(135° - 45°) + 4)
… = √(20 + 16 cos(90°))
… = √20 = 2√5