2=6-3 is the direct variation
a. There are four 5s that can be drawn, and
ways of drawing any three of them. There are
ways of drawing any three cards from the deck. So the probability of drawing three 5s is

In case you're asked about the probability of drawing a 3 or a 5 (and NOT three 5s), then there are 8 possible cards (four each of 3 and 5) that interest you, with a probability of
of getting drawn.
b. Similar to the second case considered in part (a), there are now 12 cards of interest with a probability
of being drawn.
c. There are four 6s in the deck, and thirteen diamonds, one of which is a 6. That makes 4 + 13 - 1 = 16 cards of interest (subtract 1 because the 6 of diamonds is being double counted by the 4 and 13), hence a probability of
.
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Note:
is the binomial coefficient,

Answer:
<u>If A and B are independent events, P(A and B) = P (A) * P (B)</u>
Step-by-step explanation:
Let's recall that independent events means that when one event occurs, it has no impact or influence on the probability of another event occurring. Here’s an example. Let’s say that we have two events, A and B.
Event A : it rains in Seattle
Event B : the Super Bowl match is cancelled in Miami
The two events are independent; if it rains in Seattle, this will have no impact on the probability that the Super Bowl match is cancelled in Miami. Raining in Seattle and the cancellation of the Super Bowl are independent events, therefore:
<u>P(A and B) = P (A) * P (B)</u>
F(q)=0
so, q^2 - 125 = 0
(q)^2 - (5)^2 = 0
(q+5) (q-5) = 0
q = 5, -5