THE ANSWER IS LOOK AND FIGURE WHERE IT GOES LIKE THIS IS EASY JUST PAY ATTENTION
Answer:
The sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is <u>169</u>
Step-by-step explanation:
Given : the difference of the squares of the numbers is 5 and the product of the numbers is 6.
We have to find the sum of the squares of two numbers whose difference and product is given using given identity,

Since, given the difference of the squares of the numbers is 5 that is 
And the product of the numbers is 6 that is 
Using identity, we have,

Substitute, we have,

Simplify, we have,


Thus, the sum of the squares of two numbers whose difference of the squares of the numbers is 5 and the product of the numbers is 6 is 169
Answer:
312π mm³
Step-by-step explanation:
Given:
Oblique cone height, h = 14 mm
radius of half sphere = base radius of cone, r = 6 mm
Recall the volume of 1/2 - sphere
= 1/2 x volume of sphere
= 1/2 x (4π/3) r³
= 1/2 x (4π/3) (6)³
= 144π
Also volume of an oblique cone =
=volume of a right cone
= (π/3) r²h
= (π/3) 6²(14)
=168π
Volume of composite figure = 144π + 168π = 312π mm³
Step-by-step explanation:
First
Outer
Inner
Last
First- 5x*2x=10x^2
Outer-5x*-1= -5x
Inner--7*2x= -14x
Last- -7*-1= 7
10x^2-5x-14x+7
you can simplify it further however thats the answer
Ok -7-7=-14 because your subtracting a negative with a negative and then it will be a negative then if you multiply a negative and a negative it will be a positive