The probability would be 39.9%
The given probability states that 39.9% of the 3 years olds are in daycare. Therefore, it would be obvious to assume that if you randomly selected a 3 year old, that would be the probability that he/she is in daycare.
Answer:
8/10 or 16/20
Step-by-step explanation:
Answer:
glasses of milk=4
quatar pounds servings of meat =5
two slices of whole grains bread =8
Step-by-step explanation:
Let m= milk
r=meat
b=bread
0.1m+3.4r+2.2b=35 (1)
8.5m+22r+10b=224 (2)
m+20r+12b=200 (3)
Multiply (1) by 85 and (2) by 1
8.5m+289r+187b=2,975 (4)
8.5m+22r+10b=224 (5)
Subtract (5) from (4)
267r+177b=2,751 (6)
Recall,
8.5m+22r+10b=224 (2)
m+20r+12b=200 (3)
Multiply (2) by 1 and (3) by 8.5
8.5m+22r+10b=224 (7)
8.5m+170r+102b=1700 (8)
Subtract (7) from (8)
148r+92b=1,476 (9)
Recall,
267r+177b=2,751 (6) and
148r+92b=1,476 (9)
Multiply (6) by 148 and (9) by 267
26196b=407,148 (10)
24564b=394,092 (11)
Subtract (11) from (10)
1,632b=13,056
Divide both sides by 1,632
b=13,056/1,632
b=8
Substitute the value of b in (9)
148r+92b=1,476 (9)
148r+92(8)=1,476
148r+736=1,476
148r=1,476-736
148r=740
Divide both sides by 148
r=740/148
r= 5
Substitute the value of b and r in (1)
0.1m+3.4r+2.2b=35 (1)
0.1m+3.4(5)+2.2(8)=35
0.1m+17+17.6=35
0.1m+34.6=35
0.1m=35-34.6
0.1m=0.4
Divide both sides by 0.1
m=0.4/0.1
m=4
4 glasses of milk, 5 quatar pounds servings of meat and 8 two slices of whole grains bread will supply the required nutrients.
