Since 9 is 3², each digit in base nine takes two digits in base 3.
2₉ = 02₃
6₉ = 20₃
7₉ = 21₃
1₉ = 01₃
Putting it together
2671₉ = 2202101₃
Answer:
The answer to your question is AC = 14
Step-by-step explanation:
To solve this problem, we must use trigonometric functions.
And we must look for a trigonometric function that relates the opposite side and the hypotenuse.
This trigonometric function is the sine

solve for Opposite side = AC
AC = hypotenuse x sin α
- Substitution
AC = 25 x sin 34
- Simplification
AC = 25 x 0.56
- Result
AC = 14
Answer:
I'm pretty sure it's (0,1)
Answer:
Hey there!
7-1-299-689+478*84588
7-1-299-689+40433064
40432082
Let me know if this helps :)
Notation
I imagine that the expression you are asked to work with is:

When you use a keyboard it is customary to use "^" to denote an exponent is coming so you could have written: 3x^3y+15xy-9x^2y-45y just to be clear.
PART A
To factor out the GCF we are looking for the greatest factor among the terms. Looking at the coefficients (the numbers) the largest number they can all be divided by is 3 so we will pull out a 3. Notice also that each term has a y in it so we can pull out that.
This gives us:

To factor is to write as a product (something times something else). It undoes multiplication so in this case if you take what we got and multiplied it back you should get the expression we started with.
PART B
Start with the answer in part A. Namely,

. For now let's focus only on what is in the parenthesis. We have four terms so let's take them two at a time. I am separating the expression in two using square brackets.
![[( x^{3}+5x)]-[3 x^{2} -15]](https://tex.z-dn.net/?f=%5B%28%20x%5E%7B3%7D%2B5x%29%5D-%5B3%20x%5E%7B2%7D%20-15%5D)
Let's next factor what is in each bracket:
![[( x^{3}+5x)]-[3 x^{2} -15] = [x( x^{2} +5)]-[3( x^{2} +5)]](https://tex.z-dn.net/?f=%5B%28%20x%5E%7B3%7D%2B5x%29%5D-%5B3%20x%5E%7B2%7D%20-15%5D%20%3D%20%5Bx%28%20x%5E%7B2%7D%20%2B5%29%5D-%5B3%28%20x%5E%7B2%7D%20%2B5%29%5D)
Notice that both brackets have the same expression in them so now we factor that out:
![[x( x^{2} +5)]-[3( x^{2} +5)] = (x-3)( x^{2} +5)](https://tex.z-dn.net/?f=%20%5Bx%28%20x%5E%7B2%7D%20%2B5%29%5D-%5B3%28%20x%5E%7B2%7D%20%2B5%29%5D%20%3D%20%28x-3%29%28%20x%5E%7B2%7D%20%2B5%29)
Our original expression (the one we started the problem with) had a 3y we already pulled out. We need to include that in the completely factored expression. Doing so we get: