Answer:
The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 20 - 1 = 19
90% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.7291
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample. For this question, we have
. So



The margin of error of the 90% confidence interval of a student's average typing speed is of 1.933 wpm.
Answer:
5620.52142857
Step-by-step explanation:
Rounded 5620.52
Your Welcome : )
Answer: The tenth term in the sequence is 512.
Step-by-step explanation:
Since we have given that

We need to find the tenth term:
It means n = 10
So, it becomes

Hence, the tenth term in the sequence is 512.
It opens down.
Since the beginning number -5x^2 is negative, it will open down.
Yes, you made an algebraic error. By multiplying 18 x 4, you messed up on order of operations.
(x+9)(x+2)*4
becomes:
(x^2+11x+18)*4
= 4x^2 + 44x + 72
anyway, this is how I would do this problem:
(x+9)(x+2)(4) = 912
(x+9)(x+2) = 228
x^2 + 11x + 18 = 228
x^2 + 11x - 220 = 0
(x+21)(x-10) = 0
x = -21 or 10
The dimensions can't be negative, so we only use x = 10
The dimensions are then 10+9, 10+2, 4
or 19, 12, 4