1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
pochemuha
2 years ago
6

George is cooking an elaborate meal. He can only cook one thing at a time in his microwave oven. His turkey takes 90 ​minutes; t

he pumpkin pie takes 20 ​minutes; rolls take 60 ​seconds; and a cup of coffee takes 45 seconds to heat. How much time does he need to cook the​ meal? When does he need to start in order to complete the cooking at 4 ​P.M.?
Mathematics
1 answer:
AysviL [449]2 years ago
5 0
<h2>Answer :</h2>
  • He need 111.75 minutes to cook the meal
  • He need to start at 2.08.15 P.M. in order to complete the cooking at 4 P.M.

<h2>Step-by-step explanation :</h2><h3>Known :</h3>
  • George can only cook one thing at a time
  • Turkey takes 90 minutes to cook
  • Pumpkin pie takes 20 minutes to cook
  • Rolls take 60 seconds to cook
  • A cup of coffee takes 45 seconds to heat

<h3>Asked :</h3>
  • Time needed to cook the meal
  • Time he need to start in order to complete the cooking at 4 P.M.

<h3>Completion :</h3>

Let's convert all the seconds to minutes. We know that 60 seconds is equal to one minute. So,

60 seconds = 1 minutes

45 seconds = 45/60 minutes = 0.75 minutes

Time needed = Turkey + Pumpkin pie + Rolls + Coffee

Time needed = 90 + 20 + 1 + 0.75

Time needed = 111.75 minutes

Then, we'll calculate the time he need to start in order to complete the cooking at 4 P.M. First, let's convert the minutes to clock format.

111.75 minutes = 1 hour and 51.75 minutes

111.75 minutes = 1 hour and 51 minutes and 45 seconds

Lastly, calculate the time he need to start in order to complete the cooking at 4 P.M.

4h 0m 0s - 1h 51m 45s = 2h 8m 15s

<h3>Conclusion :</h3>
  • He need 111.75 minutes to cook the meal
  • He need to start at 2.08.15 P.M. in order to complete the cooking at 4 P.M.
You might be interested in
For the function defined by f(t)=2-t, 0≤t&lt;1, sketch 3 periods and find:
Oksi-84 [34.3K]
The half-range sine series is the expansion for f(t) with the assumption that f(t) is considered to be an odd function over its full range, -1. So for (a), you're essentially finding the full range expansion of the function

f(t)=\begin{cases}2-t&\text{for }0\le t

with period 2 so that f(t)=f(t+2n) for |t| and integers n.

Now, since f(t) is odd, there is no cosine series (you find the cosine series coefficients would vanish), leaving you with

f(t)=\displaystyle\sum_{n\ge1}b_n\sin\frac{n\pi t}L

where

b_n=\displaystyle\frac2L\int_0^Lf(t)\sin\frac{n\pi t}L\,\mathrm dt

In this case, L=1, so

b_n=\displaystyle2\int_0^1(2-t)\sin n\pi t\,\mathrm dt
b_n=\dfrac4{n\pi}-\dfrac{2\cos n\pi}{n\pi}-\dfrac{2\sin n\pi}{n^2\pi^2}
b_n=\dfrac{4-2(-1)^n}{n\pi}

The half-range sine series expansion for f(t) is then

f(t)\sim\displaystyle\sum_{n\ge1}\frac{4-2(-1)^n}{n\pi}\sin n\pi t

which can be further simplified by considering the even/odd cases of n, but there's no need for that here.

The half-range cosine series is computed similarly, this time assuming f(t) is even/symmetric across its full range. In other words, you are finding the full range series expansion for

f(t)=\begin{cases}2-t&\text{for }0\le t

Now the sine series expansion vanishes, leaving you with

f(t)\sim\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi t}L

where

a_n=\displaystyle\frac2L\int_0^Lf(t)\cos\frac{n\pi t}L\,\mathrm dt

for n\ge0. Again, L=1. You should find that

a_0=\displaystyle2\int_0^1(2-t)\,\mathrm dt=3

a_n=\displaystyle2\int_0^1(2-t)\cos n\pi t\,\mathrm dt
a_n=\dfrac2{n^2\pi^2}-\dfrac{2\cos n\pi}{n^2\pi^2}+\dfrac{2\sin n\pi}{n\pi}
a_n=\dfrac{2-2(-1)^n}{n^2\pi^2}

Here, splitting into even/odd cases actually reduces this further. Notice that when n is even, the expression above simplifies to

a_{n=2k}=\dfrac{2-2(-1)^{2k}}{(2k)^2\pi^2}=0

while for odd n, you have

a_{n=2k-1}=\dfrac{2-2(-1)^{2k-1}}{(2k-1)^2\pi^2}=\dfrac4{(2k-1)^2\pi^2}

So the half-range cosine series expansion would be

f(t)\sim\dfrac32+\displaystyle\sum_{n\ge1}a_n\cos n\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}a_{2k-1}\cos(2k-1)\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}\frac4{(2k-1)^2\pi^2}\cos(2k-1)\pi t

Attached are plots of the first few terms of each series overlaid onto plots of f(t). In the half-range sine series (right), I use n=10 terms, and in the half-range cosine series (left), I use k=2 or n=2(2)-1=3 terms. (It's a bit more difficult to distinguish f(t) from the latter because the cosine series converges so much faster.)

5 0
4 years ago
Help pleaseeeeeeeeeeeeee
barxatty [35]

Answer:

a

Step-by-step explanation:

5 0
3 years ago
what is the rate of change and initial value for this graph?
MAXImum [283]

Answer:

4/7

Step-by-step explanation:

the rate of change (aka slope) is the change in y over change in x and as y goes up 4 x goes up 7 so the rate of change is 4/7

have a great day :D

8 0
3 years ago
What property is this: 3 * 1/3 = 1
Rama09 [41]

Answer:

Inverse property of multiplication

3 0
3 years ago
Jason completed the problem below and made an
stepan [7]
He didn’t divide before he multiplied
4 0
3 years ago
Other questions:
  • Which of the following represents a statistical question?
    14·1 answer
  • I understand 560-500 over 500. But why is it multiplied by 100?
    9·1 answer
  • Algebra 1 help please
    8·1 answer
  • Kitchen tiles cost £2.75 each<br> work out the total cost for 62 tiles
    9·2 answers
  • In Practing Partial Products Multiplictaion What im Going to do to 65 × 32 ?​
    14·1 answer
  • Riley rakes 1/6 of a lawn in 2/3 hour. How many lawns can Riley rake per hour?
    9·1 answer
  • Find the mean of the first six multiples of 4
    13·1 answer
  • Could someone help a girl out?
    13·2 answers
  • And is in group 38 Rock she can put them into groups of 10 rocks or as single rocks what are the different ways Ann can group th
    13·2 answers
  • QUICK?!!<br> For each ordered pair, determine whether it is a solution to 3x-5y=-13
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!