Solve each system of linear equations by substitution.

2 answers:

6 0

3x-2y=9 will be
3x-9=2y and
(3x)/2-9/2=y

2) y=2x-7

if you mean the intersection , so y=y
(3x)/2-9/2=2x-7
1,5x-4,5=2x-7
-4,5+7=2x-1,5x
2,5=0,5x
x=2,5/0,5
x=5 is the answer

Naddik [55]2 years ago

3 0

$3x-2(2x-7)=9 \\ 3x-4x+14=9 \\ -x+14=9 \\ -14\ \ \ \ -14 \\ -x=-5 \\ /-1/-1 \\ \ \ x=5$

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Select interior, exterior, or on the circle (x - 5) 2 + (y + 3) 2 = 25 for the following point. (2, 3)

lozanna [386]

Standard equation of a circle: (x-h)² + (y-k)² = r² where (h, k) is the center and r is the radius. In the case of our equation here, (x-5)² + (y+3)² = 25, we can conclude that our circle has a center at (5, -3) and a radius of 5 units.

We can use the distance formula with the center (5, -3) and our point (2, 3) to see how far away they are...if the distance between them is less than the radius of the circle, it is on the interior. If it's equal, it's on the circle. If it's greater, it's on the exterior.

Distance = $\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

Distance = $\sqrt{(-3-3)^2+(5-2)^2}$

Distance = $\sqrt{(-6)^2+3^2}$

Distance = $\sqrt{36+9}$

Distance = $\sqrt{45}\approx6.7082$

$6.7082>5,\ so\ (2,3)\ is\ on\ the\ \boxed{exterior}$