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snow_lady [41]
3 years ago
13

Round 57,386 to the nearest thousand

Mathematics
2 answers:
aliya0001 [1]3 years ago
7 0
If we need to round it to the nearest thousand, the answer will be 57,000.
DochEvi [55]3 years ago
5 0
57 thousand. Since 3 is closer to 0 than it is to 10
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7 0
2 years ago
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shtirl [24]
The correct option is: Option (B) \sum_{i=1}^{7} (5i-2)

Explanation:

First thing is that the difference between each number in the series with the next number is 5. It means it must be the multiple of 5. There are two options that contain multiples of 5: Option B and Option D. Now in the option D, the upper limit is 6. If we put 6 in the expression: 5(6)-2, the last term would be 28. However in the series given in the question, the last term is 33. Hence 5(7) - 2 = 35 - 2 = 33 which is Option B.

When i=1: 5(1)-2 = 3
When i=2: 5(2)-2 = 8
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.
.
When i=7: 5(7)-2 = 35-2 = 33
Hence the correct option is (B).
3 0
3 years ago
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