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liq [111]
3 years ago
9

What are the factor pairs for 60

Mathematics
2 answers:
Komok [63]3 years ago
7 0
The factor pairs of 60 are 1 x 60, 2 x 30, 3 x 20, 4 x 15, 5 x 12 and 6 x 10. The product of each of these number pairs is 60.
goldenfox [79]3 years ago
7 0
These are all the factor pairs: <span>1 x 60, 2 x 30, 3 x 20, 4 x 15, 5 x 12 and 6 x 10.</span>
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A rectangular pool contains 920 cubic meters of water. the pool is .4 meter deep and 100 meters wide. How long is the pool?
LekaFEV [45]
Hi there,

Sol:
Length of the swimming pool = 260 m
Breadth of the swimming pool = 140 m

Let the height of the water in the swimming pool after pouring water be h meters.

Volume of the water poured = 54600 m3

l x b x h = 54600
260 x 140 x h = 54600
h = (54600) / (260 x 140)
h = 1.5 m = 150 cm

Hope it helps
5 0
3 years ago
Show work please.<br><br> solve system of equations using matrices.
nadya68 [22]

Answer:

(t, t -1, t)

Step-by-step explanation:

You have three unknowns but only 2 equations, so you can't really SOLVE this...you can get a solution with a variable still in it (I forget what this is called.  I think it refers to infinite many solutions).  Here's how it works:

Set up your matrix:

\left[\begin{array}{ccc}1&-2&1\\2&-1&-1\\\end{array}\right] \left[\begin{array}{ccc}2\\1\\\end{array}\right]

You want to change the number in position 21 (the 2 in the scond row) to a 0 so you have y and z left.  Do this by multiplying the top row by -2 then adding it to the second row to get that 2 to become a 0.  Multiplying in a -2 to the top row gives you:

\left[\begin{array}{ccc}-2&4&-2\\2&-1&-1\\\end{array}\right]\left[\begin{array}{ccc}-4\\1\\\end{array}\right]

Then add, keeping the first row the same and changing the second to reflect the addition:

\left[\begin{array}{ccc}-2&4&-2\\0&3&-3\\\end{array}\right] \left[\begin{array}{ccc}-4\\-3\\\end{array}\right]

The second equation is this now:

3y - 3z = -3.  Solving for y gives you y = z - 1.  Let's let z = t (some random real number that will make the system true.  Any number will work.  I'll show you at the end.  Just bear with me...)

lf z = t, and if y = z - 1, then y = t - 1.  So far we have that y = t - 1 and z = t.  Now we solve for x:

From the first equation in the original system,

x - 2y + z = 2.  Subbing in t - 1 for y and t for z:

x - 2(t - 1) + t = 2.  Simplify to get

x - 2t + 2 + t = 2  and  x - t = 0, and x = t.  So the solution set is (t, t - 1, t).  Picking a random value for t of, let's say 2, sub that in and make sure it works.  If:

x - 2y + z = 2, then t - 2(t - 1) + t = 2 becomes t - 2t + 2 + t = 2, and with t = 2, 2 - 2(2) + 2 + 2 = 2.    Check it:  2 - 4 + 4 = 2 and 2 = 2.  You could pick any value for t and it will work.

6 0
3 years ago
A hockey player hits a puck along the ice, giving it an initial speed of 2.9 meters per second. If there is no friction between
Alborosie
2.9 × 1.7 = 4.93

After 1.7 seconds, the puck's speed would be 4.93 meters per second.
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3 years ago
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MrRa [10]

Answer:

Height of the ball after 3 seconds = 27.4 feet.

Step-by-step explanation:

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h(3) means the height of the ball at time 3 seconds after the ball was thrown.

h(3) = -4.9(3)^2 + 22(3) + 5.5

=  27.4 feet

5 0
3 years ago
A carpenter is installing a circular light fixture with a diameter of 6 inches in the ceiling. To do this, she must cut a square
Effectus [21]

Answer:

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Step-by-step explanation:

5 0
2 years ago
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