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Crank
3 years ago
14

Find the inverse of the function. f(x) = x^3 - 3

Mathematics
2 answers:
11111nata11111 [884]3 years ago
7 0
  1. Answer:
  2. <u>f{(x)} = {x}^{3}  - 3 \\ y =  {x}^{3}  - 3 \\ x =  {y}^{3}  - 3 \\ x + 3 =  {y}^{3}  \\  \sqrt[3]{x + 3}  = y \\  {f(x)}^{ - 1}  =   \sqrt[3]{x + 3}</u>

slavikrds [6]3 years ago
3 0

let,

y = f(x)

y = x^3 - 3

<u>Interchanging</u> <u>x</u><u> </u> <u>and</u><u> </u> <u>y</u><u> </u>,

x = y^3 - 3

x + 3 = y^3

(x + 3)^1/3 = y

◆ f^-1 (x) = (x + 3)^1/3

It is Right Answer...

Thank you♥♥

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A Chef prepares and evenly divides s ounces of beef stock into 3 smaller pans. The chef uses 8 ounces of beef stock form one of
saw5 [17]

Answer:

Thus, the equation hat correctly represents the number of ounces of beef stock, s, that the chef initially prepares.

⇒ \frac{s}{3}-8=34

The total number of ounces of beef stock = 126

Step-by-step explanation:

Given:

Total ounces of beef stock = s

The chef divided the beef stock  evenly into 3 smaller pans.

The chef then uses 8 ounces from one of the smaller pans.

Ounces of beef stock left in the smaller pan = 34

Solution:

Total ounces of beef stock = s

Ounces of beef stock in each smaller pan = \frac{s}{3}

Ounces of beef stock used by the chef from the smaller pan = 8.

The ounces of beef stock left in the smaller pan will be given as:

⇒ \frac{s}{3}-8

Ounces of beef stock remaining in smaller pan = 34

Thus, the equation hat correctly represents the number of ounces of beef stock, s, that the chef initially prepares.

⇒ \frac{s}{3}-8=34

Solving for s.

Adding 8 both sides.

⇒ \frac{s}{3}-8+8=34+8

⇒ \frac{s}{3}=42

Multiplying both sides by 3.

⇒ 3\times \frac{s}{3}=42(3)

∴ s=126

Thus, total number of ounces of beef stock = 126

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The cardinality of a set refers to the number of elements in the set. It is found by counting  the elements in the set.

<h3>What is cardinality of a set?</h3>

The cardinality of a set refers to the number of elements in the set. To obtain the cardinality, we have to count the elements in the set.

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b) There is only one element in the set hence its cardinality is 1.

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