Answer:
19.3 years
Step-by-step explanation:
Given that the initial mass of a sample of Element X is 100 grams,
The formula is given as:
N(t) = No × (1/2) ^t/t½
Element X is a radioactive isotope such that every 30 years, its mass decreases by half.
N(t) = Mass after time (t)
No = Initial mass = 100 grams
t½ = Half life = 30 grams
N(t) = 100 × (1/2) ^t/30
How long would it be until the mass of the sample reached 64 grams, to the nearest tenth of a year?
This means we are to find the time
N(t) = 100 × (1/2) ^t/30
N(t) = 64 grams
64 = 100(1/2)^t/30
Divide both sides by 100
64/100 = 100(1/2)^t/30/100
0.64 = (1/2)^t/30
Take the Log of both sides
log 0.64 = log (1/2)^t/30
log 0.64 = t/30(1/2)
t = 19.315685693242 years
Approximately = 19.3 years
The answer i got was D-17.2 units. i used the distance formula to solve this problem
Answer:
Step-by-step explanation:
Let x = third side
Using the Triangle Inequality theorem which states that the sum of two sides of a triangle must be longer than the third side and the difference of the two sides is the lower limit of the third side, the answer to your question is that the third side must be between 3 and 13, or written using inequalities, 3 < third side (or x) < 13 is the range.
Answer:
Step-by-step explanation:
idk
34. 65 = 3/4c - 7....add 7 to both sides
65 + 7 = 3/4c...simplify
72 = 3/4c...multiply both sides by 4/3, eliminating the 3/4 on the left
72 * 4/3 = c
288/3 = c
96 = c
36. -5/2 = 3/4z + 1/2 ...subtract 1/2 from both sides
-5/2 - 1/2 = 3/4z .... simplify
-6/2 = 3/4z ....reduce
-3 = 3/4z....multiply by 4/3. eliminating the 3/4 on the left
-3 * 4/3 = z
-12/3 = z
-4 = z
