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Fed [463]
2 years ago
12

The radiuses of two intersecting circles are 17 and 39. The distance between their centers is 44. Find the length of their commo

n chord
Mathematics
1 answer:
antoniya [11.8K]2 years ago
3 0

Answer:

If x is the distance from centre fo the circle, with radius 25cm, to its intersection point with the common chord, x²+24²=25² =>x=7cm.

Distance from this intersecting point to the centre of the other circle=39–7=32cm

Ratio of the sides of the right triangle thus formed is 24:32=3:4. Since 3:4:5 is the basic pythagorean triplet, the radius of the other circle=5*24/3=40cm.

Aliter: radius of the other circle=√32²+24²= 40cm.

<h2><em>please</em><em> </em><em>mark</em><em> me</em><em> as</em><em> brainalist</em></h2>
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PIT_PIT [208]

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=========================================================

Explanation:

Let's find the expression for angle TUS in terms of x

Angle TUA has the expression 11x+2. It will add to angle TUS to get 180 degrees

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--------------------------

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Solving this should lead to x = 11 to generate the angles mentioned earlier.

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