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3 years ago

Solve the system of equations using the Addition method. 2a + 3b = -1 3a + 5b = -2

1 answer:

8 0

2a + 3b = -1
3a + 5b = -2

3(2a + 3b = -1) --> 6a + 9b = -3
2(3a + 5b = -2) --> 6a + 10b = -4
- ___________
b = -1

2a + 3(-1) = -1
2a - 3 = -1
2a = 2
a = 1

2(1) + 3(-1) = -1 --> 2 - 3 = -1
3(1) + 5(-1) = -2 --> 3 - 5 = 2

Answer:
a = 1
b = -1

Hope this helps.

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What are the solutions of x^2-2x+5=0

sweet [91]

The solution of $x^{2}-2 x+5=0$ are 1 + 2i and 1 – 2i

Solution:

Given, equation is $x^{2}-2 x+5=0$

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ --- (1)

Let us determine the nature of roots:

Here in $x^{2}-2 x+5=0$ a = 1 ; b = -2 ; c = 5

$b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16$

Since $b^2 - 4ac < 0$ , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

$x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}$

On solving we get,

$x=\frac{2 \pm \sqrt{4-20}}{2}$

$x=\frac{2 \pm \sqrt{-16}}{2}$

$x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}$

we know that square root of -1 is "i" which is a complex number

$\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}$

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

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3 years ago

Help! Can someone find the area of this trapezoid?

Alex73 [517]

Answer:

192

Step-by-step explanation: idk tho so it might be right ok so dont get mad at me

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Read 2 more answers

Plz solve ill give brainliest to the first correct answer

Anastasy [175]

Answer:

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Step-by-step explanation:

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2 years ago

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Misha Larkins [42]

Answer:

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Step-by-step explanation:

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3 years ago

What is the value of |–3.25| ?

34kurt

Answer:

3.25

Step-by-step explanation:

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