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soldi70 [24.7K]
2 years ago
10

Glen invited 25 people to his birthday party.

Mathematics
1 answer:
Trava [24]2 years ago
8 0

Answer:

20% of the invited people did not attend

Step-by-step explanation:

5 out of 25 people invited didn't attend Glen's party. That means the following:

\frac{5}{25}  people didn't come which simplifies to  \frac{1}{5}

Multiply \frac{1}{5} by the giant one \frac{20}{20} so the denominator is 100 which is the denominator used to find percentages.

You end up with \frac{20}{100}

\frac{20}{100} = 20%

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Please help! I will mark as brainliest. <3
LuckyWell [14K]

Answer:

Tye required equation will be

Y = 50c+200

Step-by-step explanation:

hope it helps

8 0
3 years ago
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A candy store sells 8-pound bags of mixed hazelnuts and cashews. If c pounds of cashews are in a bag, the price p of the bag can
DochEvi [55]

A candy store sells 8 pound bags of mixed almonds and cashews. If c pounds of cashews are in a bag,...

c=1 was already given as described. The store sells pound bags.

The rest of the description and question seem not to match. Maybe each bag contains 8 pounds of the two nuts. Eight pounds and some of this is of cashews. Now, c is how many pounds of cashews in one bag.

-

 

p=2.59%2Ac%2B1.72%288-c%29

You want to know the quantity of cashews if p=18.11 dollars per bag.

2.59c%2B1.72%2A8-1.72c=p

2.59c-1.72c=p-1.72%2A8

%282.59-1.72%29c=p-1.72%2A8

0.87c=p-13.76

7 0
2 years ago
Jeremiah plans on building a 5 meter long garden walkway that is paved with square stones that measure LaTeX: \frac{5}{6}5 6 met
yan [13]

Answer:

Example 1

A backyard farmer wants to enclose a rectangular space for a new garden. She has purchased 80 feet of wire fencing to enclose 3 sides, and will put the 4th side against the backyard fence. Find a formula for the area enclosed by the fence if the sides of fencing perpendicular to the existing fence have length

L.

In a scenario like this involving geometry, it is often helpful to draw a picture. It might also be helpful to introduce a temporary variable,

W, to represent the side of fencing parallel to the 4th side or backyard fence.

Since we know we only have 80 feet of fence available, we know that

L + W + L = 80, or more simply, 2L + W = 80. This allows us to represent the width, W, in terms of L: W = 80 – 2L

Now we are ready to write an equation for the area the fence encloses. We know the area of a rectangle is length multiplied by width, so

A = LW = L(80 – 2L)

A(L) = 80L – 2L2

This formula represents the area of the fence in terms of the variable length

L.

Example 2

Returning to our backyard farmer from the beginning of the section, what dimensions should she make her garden to maximize the enclosed area?

Earlier we determined the area she could enclose with 80 feet of fencing on three sides was given by the equation

A(L) = 80L – 2L2. Notice that quadratic has been vertically reflected, since the coefficient on the squared term is negative, so the graph will open downwards, and the vertex will be a maximum value for the area.

In finding the vertex, we take care since the equation is not written in standard polynomial form with decreasing powers. But we know that

a is the coefficient on the squared term, so a = -2, b = 80, and c = 0.

Finding the vertex:

h

=

−

80

2

(

−

2

)

=

20

,

k

=

A

(

20

)

=

80

(

20

)

−

2

(

20

)

2

=

800

The maximum value of the function is an area of 800 square feet, which occurs when

L = 20 feet. When the shorter sides are 20 feet, that leaves 40 feet of fencing for the longer side. To maximize the area, she should enclose the garden so the two shorter sides have length 20 feet, and the longer side parallel to the existing fence has length 40 feet.

Example 3

A ball is thrown upwards from the top of a 40 foot high building at a speed of 80 feet per second. The ball’s height above ground can be modeled by the equation

H(t) = –16t2 + 80t + 40.

What is the maximum height of the ball?

When does the ball hit the ground?

To find the maximum height of the ball, we would need to know the vertex of the quadratic.

h

=

−

80

2

(

−

16

)

=

80

32

=

5

2

,

k

=

H

(

5

2

)

=

−

16

(

5

2

)

2

+

80

(

5

2

)

+

40

=

140

The ball reaches a maximum height of 140 feet after 2.5 seconds.

To find when the ball hits the ground, we need to determine when the height is zero—when

H(t) = 0. While we could do this using the transformation form of the quadratic, we can also use the quadratic formula:

t

=

−

80

±

√

80

2

−

4

(

−

16

)

(

40

)

2

(

−

16

)

=

−

80

s

q

r

t

8960

−

32

Since the square root does not simplify nicely, we can use a calculator to approximate the values of the solutions:

t

=

−

80

−

s

q

r

t

8960

−

32

a

p

p

r

o

x

5.458

The second answer is outside the reasonable domain of our model, so we conclude the ball will hit the ground after about 5.458 seconds.Step-by-step explanation:

8 0
3 years ago
Identify the factors of the terms of the expression 5+6a+11b
KatRina [158]
5 + 6a + 11b

terms: 5; 6a; 11b

Factors of 5: 1; 5
Factors of 6a: 1; 2; 3; 6; a; 2a; 3a; 6a
Factors of 11b: 1; 11; b; 11b
4 0
3 years ago
Help me please with that one
zubka84 [21]
The length of the wall would be 52 inches,why because you know that i inch iss 6 ft and because you already have 8 inches go ahead and multiply 8 by 6 and you get 48. you need to figure out what is 2/3 of 6 and it is 4 because 2 goes into 6 three times so 2+2 is 4. let me know if this helps you at all or if you have any questions
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3 years ago
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