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zalisa [80]
3 years ago
10

In ΔOPQ, o = 500 cm, p = 600 cm and q=380 cm. Find the measure of ∠P to the nearest 10th of a degree.

Mathematics
1 answer:
TEA [102]3 years ago
4 0

Answer: 84.8°

Step-by-step explanation:

a²+b²+c²-2bc(cosA)

cosA = b² + c² - a² / 2bc

That is the formula we will be using.

Then, plug in our numbers.

cosP= 500² + 380² - 600² / 2(500)(380)

cosP= 34400/380000

cosP≈ 0.09052631

cos⁻¹(0.09052631) ≈ 84.81

∠P = 84.8°

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Answer:

f'(x) = 4x^2 - 3 for x \le -3

Step-by-step explanation:

See attachment for proper question

Given

f(x) = -\frac{1}{2}\sqrt{x + 3}

For

x \ge -3

Required

Determine the inverse function

f(x) = -\frac{1}{2}\sqrt{x + 3}

Replace f(x) with y

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Swap the positions of x and y

x = -\frac{1}{2}\sqrt{y + 3}

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